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natima [27]
3 years ago
7

The end of a garden hose is enclosed in a mesh sphere of radius 4 cm. If the hose delivers five liters per minute, how much wate

r flows through the sphere each minute?
Physics
1 answer:
lana [24]3 years ago
6 0

Answer

0.001339 liter

Explanation:

It is given that radius = 4 cm =0.04 m

volume of sphere V=\frac{4}{3}\pi R^{3}

V=\frac{4}{3}\times 3.14\times (4\times 10^{-2})^{3}=2.674\times 10^{-4}

It is given that hose delivers five liters per minute

So the water flows through sphere per minute is given by 5×2.674×10^{-4}=0.001339 liters

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Horizontal translation of six units

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The index of refraction of silicate flint glass for red light is 1.620 and for violet light is 1.660 . A beam of white light in
Alinara [238K]

Answer:

The angular separation between the red and violet components of the spectrum that emerges from the glass is 1.72°

Explanation:

Given:

Refractive index for red light n _{1} = 1.620

Refractive index for violet n' _{1} = 1.660

Refractive index for air n_{2} = 1

Incident angle \theta _{1} = 28.30°

According to the snell's law,

    n_{1} \sin \theta _{1} = n_{2}   \sin \theta _{2}

For red light,

  1.620 \times \sin 28.30 = 1 \sin \theta _{2}

Where \theta _{2} = transmitted angle for red light

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For violet light,

  1.660 \times \sin 28.30 = 1 \sin \theta' _{2}

Where \theta' _{2} = transmitted angle for violet light

   \theta' _{2} = 51.9°

Angular separation between red and violet light is given by,

  \theta ' _{2} - \theta _{2} = 51.9 -50.18 = 1.72°

Therefore, the angular separation between the red and violet components of the spectrum that emerges from the glass is 1.72°

6 0
3 years ago
Briefly describe the difference between the amplitude of a wave (such as a light wave) and the frequency of light (again, such a
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Answer:

a wave has a trough (lowest point) and a crest (highest point). The vertical distance between the tip of a crest and the wave’s central axis is known as its amplitude. This is the property associated with the brightness, or intensity, of the wave. The horizontal distance between two consecutive troughs or crests is known as the wavelength of the wave. Keep in mind that some waves (including electromagnetic waves) also oscillate in space, and therefore they are oscillating at a given position as time passes. The quantity known as the wave’s frequency refers to the number of full wavelengths that pass by a given point in space every second; the SI unit for frequency is Hertz (\text{Hz})(Hz)left parenthesis, start text, H, z, end text, right parenthesis, which is equivalent to “per seconds” \Big((left parenthesiswritten as \dfrac{1}{\text{s}}  s

​  

start fraction, 1, divided by, start text, s, end text, end fraction or \text{s}^{-1}\Big)s  

−1

)start text, s, end text, start superscript, minus, 1, end superscript, right parenthesis. As you might imagine, wavelength and frequency are inversely proportional: that is, the shorter the wavelength, the higher the frequency, and vice versa. This relationship is given by the following equation:

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where \lambdaλlambda (the Greek lambda) is the wavelength (in meters, \text{m}mstart text, m, end text) and \nuν\nu (the Greek nu) is the frequency (in Hertz, \text{Hz}Hzstart text, H, z, end text). Their product is the constant ccc, the speed of light, which is equal to 3.00\times10^8 \text{ m/s}3.00×10  

8

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Explanation:

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4 years ago
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sukhopar [10]

Answer:0.68 D

Explanation:

Given

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From Lens Formula

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Here the object distance is infinity

\frac{1}{f}=\frac{-1}{147}+\frac{1}{\infty}

Therefore f=-147 cm

and f=\frac{1}{P}

P=-\frac{100}{147}

P=-0.68 D

8 0
3 years ago
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