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creativ13 [48]
4 years ago
7

Convert 183cm to meters Pls show the work

Physics
2 answers:
MaRussiya [10]4 years ago
4 0
Divide by 100 as there are 100cm in a metre

Answer 1.83
SCORPION-xisa [38]4 years ago
4 0

Answer:

1.83 meters

Explanation:

1 meter = 100 cm

183cm/100cm= 1.83 meters

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A less than youthful 82.6 kg physics professor decides to run the 26.2 mile (42.195 km) Los Angeles Marathon. During his months
o-na [289]
Mem me e m even have. Jags. Shah. Shiv side esicjm is n meh dish so do indbbd
4 0
3 years ago
If April launched a water balloon directly upwards with a speed of 40 m/s, how high would it be after 6 seconds? Use 10 m/s​
Volgvan

Answer:

495m

Explanation:

ANSWER

u

stone

=10m/s (initial velocity of stone)

t=11s

∴H=−ut+

2

1

gt

2

(H=height of baloon)

H=−10×11+

2

1

×10×121=605−110=495m

3 0
4 years ago
Your student desk has been in the room for many hours, it is at thermal equilibrium with the room?
Svetllana [295]

Answer:

metal because A: In general, metals feel colder or hotter to the touch than other materials at the same temperature because they're good thermal conductors. This means they easily transfer heat to colder objects or absorb heat from warmer objects. Thermal insulators like plastic and wood don't transfer heat as easily.

Explanation:

4 0
3 years ago
Are the units of the formula ma = mv2/2 dimensionally consistent? Select the single best answer.
Vesnalui [34]

To solve the problem we will simply perform equivalence between both expressions. We will proceed to place your units and develop your internal operations in case there is any. From there we will compare and look at its consistency

ma = \text{Mass}\times \text{Acceleration}

ma = kg \cdot \frac{m}{s^2}

At the same time we have that

\frac{1}{2}mv^2 = \text{Mass}\times \text{Velocity}^2

\frac{1}{2}mv^2 = kg ( \frac{m}{s})^2

\frac{1}{2}mv^2 = kg \cdot \frac{m^2}{s^2}

Therefore there is not have same units and both are not consistent and the correct answer is B.

5 0
4 years ago
Light of wavelength 650 nm is normally incident on the rear of a grating. The first bright fringe (other than the central one) i
garik1379 [7]

Answer

given,

wavelength (λ) = 650 nm

angle = 5°

using bragg's law

sin \theta = \dfrac{n \lambda}{d}

d= \dfrac{n \lambda}{sin \theta}

d= \dfrac{1 \times 650 \times 10^{-9}\ m}{sin5^0}

d = 7.46 x 10⁻⁴ cm

number of slits per centimeter

  = \dfrac{1}{d}\\\Rightarrow \dfrac{1}{7.46\times 10^{-4}}\\\Rightarrow 1340 split per centimeter.

b) wavelength of two rays  650 nm and 420 nm

 d = \dfrac{1}{5000}

     d =  2 x 10⁻6 m

    we now,

sin \theta = \dfrac{n \lambda}{d}

for 650 nm

sin \theta = \dfrac{2\times 650\times 10^{-9}}{2\times 10^{-6}}

\theta =sin^{-1}(0.65)

θ = 40.54°

for 450 nm

sin \theta = \dfrac{2\times 450\times 10^{-9}}{2\times 10^{-6}}

\theta =sin^{-1}(0.45)

θ = 24.83°

now, difference

|θ_{650} -θ_{420}| =40.54°-24.83°

|θ_{650} -θ_{420}| =19.71°

8 0
4 years ago
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