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Ber [7]
3 years ago
15

Decide whether a chemical reaction happens in either of the following situations. If a reaction does happen, write the chemical

equation for it. Be sure your chemical equation is balanced and has physical state symbols. situation chemical reaction? chemical equation A strip of solid lead metal is put into a beaker of 0.043M Fe(NO3)2 solution. yes no A strip of solid iron metal is put into a beaker of 0.044M Pb(NO3)2 solution.

Chemistry
1 answer:
iragen [17]3 years ago
6 0

Answer: The chemical equations are given below.

Explanation:

A balanced chemical reaction follows law of conservation of mass.

This law states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.  

Single displacement reaction is defined as the reaction in which more reactive metal displaces a less reactive metal from its chemical reaction.

General equation representing single displacement reaction follows:

AB+C\rightarrow CB+A

C is more reactive element than element A.

The reactivity of metals is judged by the series known as reactivity series. Elements lying above in the series are more reactive than the elements lying below in the series.

  • 1. When solid lead metal is put in the beaker of 0.043 M Fe(NO_3)_2 solution.

Lead lies below in the reactivity series than iron. Thus, it will not replace iron from its chemical reaction.

Pb(s)+Fe(NO_3)_2(aq.)\rightarrow \text{No reaction}

  • 2. When solid iron metal is put in the beaker of 0.044 M Pb(NO_3)_2 solution.

Iron lies above in the reactivity series than lead. Thus, it will easily replace lead from its chemical reaction.

Fe(s)+Pb(NO_3)_2(aq.)\rightarrow Fe(NO_3)_2(aq.)+Pb(s)

Hence, the chemical equations are given above.

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Osmosis occurs when two solutions of different concentrations are separated by a semipermeable membrane. The membrane allows sol
Finger [1]

Answer:

Part A → 7.82 atm

Part B → The unknown solution had the higher concentration

Part C →  0.83 mol/L

Explanation:

Part A

Osmotic pressure (π) = M . R. T . i

NaCl → Na⁺  +  Cl⁻ (i =2)

0.923 g of NaCl must be dissolved in 100 mL of solution.

0.923 g / 58.45 g/m = 0.016 moles

Molarity is mol/L → 0.016 m / 0.1L = 0.16M

π = 0.16M . 0.08206 L.atm/molK . 298K . 2 ⇒ 7.82atm

Part. B

The solvent moves toward the solution of higher concentration (to dilute it) until the two solutions have the same concentration, or until gravity overtakes the osmotic pressure, Π. If the level of the unknown solution drops when it was connected to solution in part A, we can be sure that had a higher concentration.

Part. C

π = M . R . T

20.1 atm = M . 0.08206 L.atm/mol.K . 294K

20.1 atm / (0.08206 L.atm/mol.K . 294K) = 0.83 mol/L

8 0
3 years ago
A part of an mrna molecule with the following sequence is being read by a ribosome: 5' ccg-acg 3' (mrna). the anticodon loop of
monitta

The first trna's anticodon loop, which will complement this mrna, is 3' GGC 5'.

<h3>What is anticodon ?</h3>

A complementary codon in messenger RNA binds to a triplet of nucleotide bases in transfer RNA that identifies the amino acid delivered during protein synthesis at a ribosome.

A codon is a trio of nucleotides, or triplet, that can be found on mRNA and codes for a certain amino acid when it is translated. A bond is created when an anticodon, which is a three-nucleotide sequence on tRNA, meets with the matching sequence on mRNA.

Each tRNA has a trio of bases known as an anti-codon. to determine the entire anti-codon sequence required to match a certain strand of mRNA. to match the complementary nucleotides in the mRNA sequence.

To learn more about anticodon from the given link:

brainly.com/question/14917337

#SPJ4

3 0
2 years ago
H2SO4 + 2NaOH → 2H2O + Na So.
gayaneshka [121]

Answer:

2 mol H

Explanation:

For every 2 mol of NaOH, we're reacting 2 mol of H2O. In order to figure out how many mol of H are needed, it needs to be set up stochiometrically. Starting off with the given value, 1 mol of NaOH, we can then make a mol to mol ratio. For 2 mol of NaOH, we have 2 mol of H2O. For every 2 mol of H2O, we have 4 mol of H (this is because we are multiplying the coefficient by the subscript: 2 × 2). Now, we can solve for our answer.

1 mol NaOH × (2 mol H₂O / 2 mol NaOH) × (4 mol H / 2 mol H₂O)

= 2 mol H

Thus, we get 2 mol of H are needed to completely react 1 mol of NaOH.

7 0
4 years ago
Which rock was subjected to intense heat and pressure but did not solidify from magma?sandstoneschistgabbrorhyolite
Serhud [2]
The answer is Rhyolite

7 0
3 years ago
How many liters of 0.615 M NaOH will be needed to raise the pH of 0.385 L of 5.13 M sulfurous acid (H2SO3) to a pH of 6.247?
givi [52]

Answer:

Volume of NaOH required = 3.61 L

Explanation:

H2SO3 is a diprotic acid i.e. it will have two dissociation constants given as follows:

H2SO3\leftrightarrow H^{+}+HSO3^{-} --------(1)

where,  Ka1 = 1.5 x 10–2  or pKa1 = 1.824

HSO3^{-}\leftrightarrow H^{+}+SO3^{2-} --------(2)

where,  Ka2 = 1.0 x 10–7 or pKa2 = 7.000

The required pH = 6.247 which is beyond the first equivalence point but within the second equivalence point.

Step 1:

Based on equation(1), at the first eq point:

moles of H2SO3 = moles of NaOH

i.e. \ 5.13\  moles/L*0.385L = moles\  NaOH\\therefore, \ moles\  NaOH = 1.98\ moles\\V(NaOH)\ required = \frac{1.98\ moles}{0.615\ moles/L} =3.22L

Step 2:

For the second equivalence point setup an ICE table:

                  HSO3^{-}+OH^{-}\leftrightarrow H2O+SO3^{2-}

Initial           1.98                    ?                                       0

Change      -x                       -x                                       x

Equil           1.98-x                 ?-x                                    x

Here, ?-x =0 i.e. amount of OH- = x

Based on the Henderson buffer equation:

pH = pKa2 + log\frac{[SO3]^{2-} }{[HSO3]^{-} } \\6.247 = 7.00 + log\frac{x}{(1.98-x)} \\x=0.634 moles

Volume of NaOH required is:

\frac{0.634\ moles}{0.615 moles/L}=0.389L

Step 3:

Total volume of NaOH required = 3.22+0.389 =3.61 L

3 0
3 years ago
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