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3 years ago

Which method is used to separate the following mixture (a) water + kerosene

Chemistry

1 answer:

Ad libitum [116K]3 years ago

8 0

Answer:

The separation of kerosene, oil, and water are immiscible liquids, so they can be separated funnel.

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Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r

denis23 [38]

Answer :

(1) The frequency of photon is, $3\times 10^{10}Hz$

(2) The energy of a single photon of this radiation is $1.988\times 10^{-23}J/photon$

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = $1.0cm=0.01m$ (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

$\nu=\frac{c}{\lambda}$

where,

$\nu$ = frequency of photon

$\lambda$ = wavelength of photon

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$\nu=\frac{3\times 10^8m/s}{0.01m}$

$\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz$ $(1Hz=1s^{-1})$

The frequency of photon is, $3\times 10^{10}Hz$

(2) Now we have to calculate the energy of photon.

Formula used :

$E=h\times \nu$

where,

$\nu$ = frequency of photon

h = Planck's constant = $6.626\times 10^{-34}Js$

Now put all the given values in the above formula, we get:

$E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})$

$E=1.988\times 10^{-23}J/photon$

The energy of a single photon of this radiation is $1.988\times 10^{-23}J/photon$

(3) Now we have to calculate the energy in J/mol.

$E=1.988\times 10^{-23}J/photon$

$E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)$

$E=11.97J/mol$

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

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3 years ago

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Answer the question below based on the periodic table entry for bromine.

Shalnov [3]

<span>The number of neutrons bromine will have are equal to
= protons + neutrons
so,
80-35=45</span>

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3 years ago

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Silicon has a relatively large latent heat of vaporization of 12800 J/g. This indicates that silicon has:

beks73 [17]

I believe it means that it takes a lot of heat in joules to make silicon vaporize so it stays solid until a great deal of heat has been added. By comparison, water has a latent heat of about 2260 joules per gram so vaporizes much more readily than silicon.

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3 years ago

PLEASE HELP

prohojiy [21]

Answer:

Mass and gravitational for e is not relart

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3 years ago

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If the density of mercury is 13.6 g/mL, what is the mass of 25.4 cm3 of<br> mercury?

Anettt [7]

Answer:

345.44 g or 0.34544 kg

Explanation:

Applying

D = m/V...................... Equation 1

Where D = Density of mercury, m = mass of mercury, V = Volume of mercury.

make m the subject of the equation

m = D×V................. Equation 2

From the question,

Given: D = 13.6 g/mL = 13.6 g/cm³, V = 25.4 cm³

Substitute these values into equation 2

m = 13.6×25.4

m = 345.44 g

m = 0.34544 kg

Hence the mass of mercury is 345.44 g or 0.34544 kg

4 0

3 years ago

Which method is used to separate the following mixture (a) water + kerosene​

Which method is used to separate the following mixture (a) water + kerosene