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ioda
3 years ago
5

Read this excerpt from "Why Are They Called Black Holes?"

Chemistry
2 answers:
Ratling [72]3 years ago
7 0

Answer: the answer is c

Explanation: hope this helps you

n200080 [17]3 years ago
7 0

Answer: the answer is c

Explanation: hope this helps you

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What is your opinion on marijuana?
jarptica [38.1K]

I think that marijuana should be legalized for recreational use.  It's not really bad for you and it doesn't cause problems like violence.  If marijuana was the most abused substance rather than alcohol it would be an improvement.

4 0
4 years ago
What are three chemical changes and what are three physical changes?
choli [55]

Chemical changes:

burning wood

digesting food

mixing acid and base

Physical changes:

breaking a bottle

melting an ice cube

crumbling a sheet of paper

8 0
3 years ago
For which of the following aqueous solutions would one expect to have the largest van’t Hoff factor (i)? a. 0.050 m NaCl b. 0.50
ira [324]

Answer:

The van't hoff factor of 0.500m K₂SO₄ will be highest.

Explanation:

Van't Hoff factor was introduced for better understanding of colligative property of a solution.

By definition it is the ratio of actual number of particles or ions or associated molecules formed when a solute is dissolved to the number of particles expected from the mass dissolved.

a) For NaCl the van't Hoff factor is 2

b) For K₂SO₄ the van't Hoff factor is 3 [it will dissociate to give three ions one sulfate ion and two potassium ions]

Out of 0.500m and 0.050m K₂SO₄, the van't hoff factor of 0.500m K₂SO₄ will be more.

c) The van't Hoff factor for glucose is one as it is a non electrolyte and will not dissociate.

7 0
3 years ago
The oxidation number of what atom or ion decreases in the following reaction?
Flauer [41]

The oxidation number of I (iodine) decreases the in the described chemical reaction from 0 to -1.

Explanation:

We have the following chemical reaction:

I₂ + 2 KCl → KI + Cl₂

The following atoms have a change in the oxidation number:

I with a 0 oxidation number (in I₂) goes to I with -1 oxidation number (in KI) by receiving 1 electron.

Cl with a -1 oxidation number (in KCl) goes to I with 0 oxidation number (in Cl₂) by losing 1 electron.

Learn more about:

oxidation number

brainly.com/question/6710925

#learnwithBrainly

7 0
3 years ago
Given the atomic radius of xenon, 1.3 ?, and knowing that a sphere has a volume of 4?r3/3, calculate the fraction of space that
34kurt
R = 1.3 A° = 1.3 × 10^(-10) m
v \:  =  \:  \frac{4}{3} \pi {r}^{3}
v \:  =  \:  \frac{4}{3}  \times 3.1415 \times  {(1.3 \times  {10}^{ - 10} )}^{3}
V = 9.20277208×10^(−30) m.
7 0
3 years ago
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