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4 years ago

5

Mountain ranges are formed by: plate collision melting of rock in the mantle evaporation of ocean waters buildup of salt and sed

iment

2 answers:

Likurg_2 [28]4 years ago

6 0

Mountain ranges are caused by "A) Plate Collision"

Anika [276]4 years ago

3 0

I'm pretty sure it's plate collision

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Which statement is true about sodium hydroxide (NaOH)?

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It's a base because it increases the concentration of hydroxid ions

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3 years ago

Read 2 more answers

Convert 364 kg to lb

miv72 [106K]

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This snip might help...it depends :)

Explanation:

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3 years ago

The names and chemical formulae of some chemical compounds are written in the first two columns of the table below. Each compoun

charle [14.2K]

Answer:

See below

Explanation:

<u> Name </u> <u>Formula </u> <u> Major species </u> <u> </u>

Zinc iodide ZnI₂ H₂O(ℓ), I⁻(aq), Zn²⁺(aq),

Nitrogen(I) oxide N₂O H₂O(ℓ), N₂O(aq)

Sodium nitrite NaNO₂ H₂O(ℓ), Na⁺(aq), NO₂⁻(aq)

Glucose C₆H₁₂O₆ H₂O(ℓ), C₆H₁₂O₆(aq)

Nickel(II) iodide NiI₂ H₂O(ℓ), I⁻(aq), Ni²⁺(aq)

Glucose and nitrogen(I) oxide are covalent compounds. They do not dissociate in solution.
The compounds containing metals are ionic. They produce ions in solution.
ZnI₂ and NiI₂ produce twice as many iodide ions as metal ions.

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4 years ago

Calculate the enthalpy for this reaction: 2C(s) + H2(g) ---> C2H2(g) ΔH° = ??? kJ Given the following thermochemical equation

nordsb [41]

Answer:

The enthalpy for given reaction is 232 kilo Joules.

Explanation:

$C_2H_2(g) + \frac{5}{2}O_2(g)\rightarrow 2CO_2(g) + H_2O(l), \Delta H^o_{1} = -1,123 kJ$ ...[1]

$C(s) + O_2(g)\rightarrow CO2(g), \Delta H^o_{2} = -340 kJ$ ..[2]

$H_2(g) + \frac{1}{2}O_2(g)\rightarrow H_2O(l) ,\Delta H^o_{3} = -211 kJ$ ..[3]

$2C(s) + H_2(g)\rightarrow C_2H_2(g),\Delta H^o_{4} =?$ ..[4]

2 × [2] + [3] - [1] ( Using Hess's law)

$\Delta H^o_{4}=2\times \Delta H^o_{2}+\Delta H^o_{3} - \Delta H^o_{1}$

$\Delta H^o_{4}=2\times (-340 kJ) + (-211 kJ) - (-1,123 kJ)$

$\Delta H^o_{4}=232 kJ$

The enthalpy for given reaction is 232 kilo Joules.

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3 years ago

Draw the structure of bromous acid, hbro2. optimize formal charges.

ArbitrLikvidat [17]

STRUCTURE OF BROMOUS ACID: H–O–Br=O

<span>In this structure, all the elements have a formal charge of zero. The formal charge of each element is calculated below: </span><span>

H: 1 – 1/2(2) – 0 = 0
O: 6 – 1/2(4) – 4 = 0
Br: 7 – 1/2(6) – 4 = 0
<span>O: 6 – 1/2(4) – 4 = 0</span></span>

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3 years ago