Question

Solve for x in the equation x^2 + 4x - 4 = 8

Answer 1

x^2+4x-4=8

Subtract 8 from both sides: x^2+4x-4-8=8-8

Simplify: x^2+4x-12=0

Solve with the quadratic formula: For a=1,b=4,c=-12: x1,2= -4+- (4^2-4*1(-12))sqrt over 2*1

x= 2 and x=-6

Answer 2

Subtracting 8 from both sides of the equation gives

x^2 + 4x - 12 = 0

(x + 6)(x - 2)= 0

x = -6, 2   answer