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True [87]
4 years ago
10

Factor. 25m100−121n16 (5m50−11n8)(5m50+11n8) (5m50−11n8)2 (5m10−11n4)2 (5m10−11n4)(5m10+11n4)

Mathematics
1 answer:
Flura [38]4 years ago
3 0

Answer:

The answer to your question is (5m50−11n8)(5m50+11n8)

Step-by-step explanation:

                                             25m¹⁰⁰−121n¹⁶

find the prime factors of 25 and 100

    25     5                                  121     11

       5     5                                   11      11

        1                                            1

25 = 5 x 5 = 5²                       121 = 11 x 11 = 11²

m¹⁰⁰ = (m⁵⁰)²                           n¹⁶ = (n⁸)²

Substitution

                     25m¹⁰⁰−121n¹⁶ = 5²(m⁵⁰)²   - 11² (n⁸)²

                                            = (5m⁵⁰  - 11n⁸)  (5m⁵⁰  + 11n⁸)

(5m50−11n8)(5m50+11n8)

(5m50−11n8)2

(5m10−11n4)2

(5m10−11n4)(5m10+11n4)

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Which graph best represents the relationship between time and the number of teams registered?
alexdok [17]
<h2>Explanation:</h2><h2></h2>

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