It takes Mike 18 minutes to finish reading 4 pages of a book. How long does it take for him to finish reading 30 pages

kaheart [24]

I don't think this is middle school...

(2^8 x 3^-5 x 6^0)^-2 x ((3^-2)/(2^3))^4 x (2^28)

(256 x (1/243))^-2 x ((1/9)/(8))^4 x 268435456

1.05349794239^-2 x (<span>0.01388888888)^4 x 268435456
</span><span>
0.90101623534 x </span><span>3.72108862e-8 x 268435456

</span>8.99999997623

9

9 is your answer.

8 0

3 years ago

Identify which line from the graph the following right triangles could lie on.

qaws [65]

Answer:

Step-by-step explanation:

Slope of line A = $\frac{\text{Rise}}{\text{Run}}$

= $\frac{9}{3}$

= 3

Slope of line B = $\frac{9}{6}$

= $\frac{3}{2}$

Slope of line C = $\frac{6}{8}$

= $\frac{3}{4}$

5). Slope of the hypotenuse of the right triangle = $\frac{\text{Rise}}{\text{Run}}$

= $\frac{90}{120}$

= $\frac{3}{4}$

Since slopes of line C and the hypotenuse are same, right triangle may lie on line C.

6). Slope of the hypotenuse = $\frac{30}{10}$

= 3

Therefore, this triangle may lie on the line A.

7). Slope of hypotenuse = $\frac{18}{24}$

= $\frac{3}{4}$

Given triangle may lie on the line C.

8). Slope of hypotenuse = $\frac{21}{14}$

= $\frac{3}{2}$

Given triangle may lie on the line B.

9). Slope of hypotenuse = $\frac{36}{24}$

= $\frac{3}{2}$

Given triangle may lie on the line B.

10). Slope of hypotenuse = $\frac{48}{16}$

= 3

Given triangle may lie on the line A.

7 0

3 years ago

Jose sold 102 raffle tickets for his basketball team. If he was given 125 tickets to sell, about what percentage of his tickets

Setler [38]

He sold about <span>80% of his tickets</span>

4 0

3 years ago

Find the limit

Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

$\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}$

$\rm \: = \sf \: \: - \infty \: - \: \infty$

which is indeterminant form.

Consider again,

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

can be rewritten as

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]$

$\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}$

$\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}$

$\rm \: = \: \sf \boxed{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}$

$\rule{190pt}{2pt}$

7 0

3 years ago

Read 2 more answers

Perform the indicated operation. (-18)/-(4)

Illusion [34]

A negative divided by a negative is always a positive. 4 can go into 18 only 4 times to get 16 with a remainder of 2. 2 is half of four, therefore -4 can go into -18 4.5 times.
The answer is 4 1/2 or 4.5.
I hope this helps ^-^

7 0

3 years ago