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2 years ago

It takes Mike 18 minutes to finish reading 4 pages of a book. How long does it take for him to finish reading 30 pages

Mathematics

1 answer:

dusya [7]2 years ago

5 0

Answer:

Step-by-step explanation:

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the average pumpkin weigh 6 lb the prize-winning pumpkin weighs 324 lb the prize-winning pumpkin weighs as much as how many aver

andrey2020 [161]

With this problem, it's essentially asking how many groups of 6 can fit into 324. We can do that simply by dividing 324 by 6 to get 54.

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2 years ago

Which system of the inequalities is shown in the graph

jolli1 [7]

Answer:

Step-by-step explanation:

the equation of the parabola is : y = x² - 3x

the equation of the line is y = x + 1

and the shaded area is between those graphs

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3 years ago

_(9)=(2(1-2(2)^(9)))/(1-2(2))<br><br><br>PLEASE HELP ME OUT.

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Answer:

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Step-by-step explanation:

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2 years ago

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Gre4nikov [31]

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D. The last 26/8, 3-32, -Pi, -4 2/3

Step-by-step explanation:

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5 months ago

Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

2 years ago