301
We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...
However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.
Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).
301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.
Hope this all makes sense.
For this case, the first thing we must do is define variables.
We have then:
x: initial amount of cards
We now write the equation that models the problem:
Therefore, the initial amount of cards is 300
Answer:
Latoya had 300 cards at the beginning
Answer:
Step-by-step explanation:
aye I need the answer soomeine helo me out, add my insta;, hy.cxsar
Answer:
A
Step-by-step explanation:
I hope this helps and sorry if I'm wrong!
Answer: Zero
Step-by-step explanation:
If you calculate -3 + 3 you get the answer of zero. Not sure if there is more to the problem.
