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3 years ago

10

IDENTIFY the ERROR. Javier wants to paint the bottom of his circular

1 answer:

Katarina [22]3 years ago

5 0

Answer:

step 3, 4 and 5 are incorrect

Step-by-step explanation:

area of a circle = 3.14(radius)squared

3.14 x 25squared

=3.14 x 625

=1962.5

tip area of circle equals "Pies are squared" $\pi$ $r^{2}$

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Julio has $150. Each week, he saves an additional $10.Write a function ()that models the total amount of money Julio has after w

nadya68 [22]

Answer:

The function that models the total amount of money Julio has after weeks is:

f(x)=150+10x, where:

x is the number of weeks

Step-by-step explanation:

With the information provided, you can say that the total amount of money Julio has would be equal to the initial amount he has plus the result of multiplying the $10 that he saves every week for the number of weeks, which can be expressed as:

f(x)=150+10x, where:

x is the number of weeks

4 0

3 years ago

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PLEASE HELP MEEEEEEEEEE

ololo11 [35]

Answer:

Step-by-step explanation:

step 2 is incorrect.

step 2: -40-75+100+200

step 3: -115+300

step 4 : 185

4 0

3 years ago

We want to find the maximum and minimum values of f(x, y) = 10x2 + 11y on the disk D: x2 + y2 < 1.

dolphi86 [110]

If you're just focusing on the boundary, it's the circle $x^2+y^2=1$ . Parameterize it by taking $x=\cos t$ and $y=\sin t$ , with $0\le t\le2\pi$ . Then $f(x,y)$ reduces to a univariate function $g(t)$ :

$f(x,y)=10x^2+11y\iff g(t)=f(\cos t,\sin t)=10\cos^2t+11\sin t$

Then you can find any extrema on the boundary by checking the critical points of $g$ .

8 0

3 years ago

Find the value of b.

Nesterboy [21]

Answer: $230^{\circ$

Step-by-step explanation:

For convenience, I labeled some points as shown in the attached picture.

Also, I assume $\overline{AB}$ and $\overline{BC}$ are tangents to the circle.

$\overline{BO} \cong \overline{BO}$ (reflexive property)
$\overline{AB} \cong \overline{BC}$ (tangents drawn from a common external point are congruent)
$\angle BAO \cong \angle BCO$ (right angles are congruent)

Therefore, we know $\triangle ABO \cong \triangle CBO$ by HL.

Thus, by CPCTC,

$\angle AOB \cong \angle BOC \implies m\angle BOC=65^{\circ}\\\\\implies m\angle AOC=130^{\circ}$

This means the measure of minor arc AC is $130^{\circ}$ , and thus $b=360^{\circ}-130^{\circ}=\boxed{230^{\circ}}$

7 0

1 year ago

Can someone tell me the answer please ?<br>

monitta

Answer:

130 degrees

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers