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2 years ago

IDENTIFY the ERROR. Javier wants to paint the bottom of his circular

Mathematics

1 answer:

Katarina [22]2 years ago

5 0

Answer:

step 3, 4 and 5 are incorrect

Step-by-step explanation:

area of a circle = 3.14(radius)squared

3.14 x 25squared

=3.14 x 625

=1962.5

tip area of circle equals "Pies are squared" $\pi$ $r^{2}$

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How to factor 8x^3-216

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$8x^3-216\to\boxed{8(x^3-27)}$

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2 years ago

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20 POINTS, and BRAINIEST

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HURRY PLEASE!! I’ll mark you as brainliest!! Solve the system: 3x + y = 10 and -4x - 2y = 2

BaLLatris [955]

Answer:

uld you like to ask?

10th

Maths

Pair of Linear Equations in Two Variables

Algebraic Solution of a Pair of Linear Equations

Solve: 3x + 4y = 10,2x - 2y...

MATHS

Asked on December 27, 2019 byShweta Rudravaram

Solve: 3x+4y=10,2x−2y=2 by the method of elimination.

EASY

Study later

ANSWER

3x+4y=10 …………..(1)

2x−2y=2 (or) x−y=1 …………(2)

(1) ⇒(3x+4y=10)1

(2) ⇒(x−y=1)3

_____________________

3x+4y=10

3x−3y=3

_____________________

7y=7

∴y=1

Put y=1 in (1) we get 3x+4×1=10

3x=10−4=6

∴x=36=2

Hence x=2,y=1.

7 0

2 years ago

A company uses two vans to transportworkers from a free parking lot to theworkplace between 7:00 and 9:00 a.m.One van has 6 more

OverLord2011 [107]

X = small van capacity, y = larger van capacity
y = x + 6

2x + y = 57
now we sub in x + 6 for y
2x + x + 6 = 57
3x + 6 = 57
3x = 57 - 6
3x = 51
x = 51/3
x = 17

y = x + 6
y = 17 + 6
y = 23

small van (x) has 17 seats and large van (y) has 23 seats

3 0

2 years ago

Dinosaur fossils are often dated by using an element other than carbon, like potassium-40, that has a longer half life (in this

Firlakuza [10]

The amount of substance left of a radioactive element of half life, $t_{\frac{1}{2}}$ after a time, t, is given by:

$N(t)=N_0\left( \frac{1}{2} \right)^ \frac{t}{t_{ \frac{1}{2} }}$

Given that potassium-40 has a half life of approximately 1.25 billion years.

The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:

$0.1=100\left( \frac{1}{2} \right)^ \frac{t}{1.25}} \\ \\ \Rightarrow\left( \frac{1}{2} \right)^ \frac{t}{1.25}}=0.001 \\ \\ \Rightarrow\frac{t}{1.25}\ln\left( \frac{1}{2} \right)=\ln(0.001) \\ \\ \Rightarrow \frac{t}{1.25}= \frac{\ln(0.001)}{\ln\left( \frac{1}{2} \right)} =9.966 \\ \\ t=9.966(1.25)=12.5$

Therefore, the maximum age of a fossil that we could date using 40k is 12.5 billion years.

3 0

2 years ago