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ratelena [41]
4 years ago
12

What is this graph 3X-2y=7

Mathematics
1 answer:
trapecia [35]4 years ago
5 0
3x-2y=7
3x=7
x=7/3

-2y=7
y=-7/2

so...(7/3,-7/2)
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A company manufactures and sells x television sets per month. The monthly cost and​ price-demand equations are ​C(x)=72,000+60x
myrzilka [38]

Answer:

Step-by-step explanation:

Given

Cost Price c(x)=72000+60x

Price p(x)=300-\frac{x}{20}

Revenue generated R(x)=P(x)\times x

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R(x)=300x-\frac{x^2}{20}

To get maxima and minima differentiate R(x)

\frac{\mathrm{d} R(x)}{\mathrm{d} x}=0

\frac{\mathrm{d} R(x)}{\mathrm{d} x}=300-2\times \frac{x}{20}=0

300=2\times \frac{x}{20}

x=3000

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(b)Profit=Revenue - cost

Profit=xp(x)-c(x)

Profit=300x-\frac{x^2}{20}-72000-60x

Profit(z)=240x-\frac{x^2}{20}-72000

differentiate Profit to get maximum value

\frac{\mathrm{d} z}{\mathrm{d} x}=240-2\times \frac{x}{20}

x=2400

maximum Profit z=2,16,000

(c)Now company decided to tax the company $ 55 for each set

Profit (z_1)=xp(x)-c(x)-55x

z_1=300x-\frac{x^2}{20}-72000x-60x^2-55x

z_1=185x-\frac{x^2}{20}-72,000

differentiate Profit to get maximum value

\frac{\mathrm{d} z_1}{\mathrm{d} x}=0

\frac{\mathrm{d} z_1}{\mathrm{d} x}=185-\frac{2x}{20}=0

x=1850

P(z_1\ at\ x=1850)=99125

company should charge 207.5 $ for each set

         

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Answer:

I Think The Answer Is 27???

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