Answer:
He will earn $140, my bad miss calculated...
Step-by-step explanation:
Its 140....
Using the three trigonometric functions can be used to calculate unknown side lengths and angle in a right-angle triangle only.
But, if ever you we're given to find a non right-angle triangle, you will have to use sine rule or cosine rule.
I believe it would be 160000
Answer:
The coordinates of the circumcenter of this triangle are (3,2)
Step-by-step explanation:
we know that
The circumcenter is the point where the perpendicular bisectors of a triangle intersect
we have the coordinates
![A(-2,5),B(-2,-1),C(8,-1)](https://tex.z-dn.net/?f=A%28-2%2C5%29%2CB%28-2%2C-1%29%2CC%288%2C-1%29)
step 1
Find the midpoint AB
The formula to calculate the midpoint between two points is equal to
![M=(\frac{x1+x2}{2},\frac{y1+y2}{2})](https://tex.z-dn.net/?f=M%3D%28%5Cfrac%7Bx1%2Bx2%7D%7B2%7D%2C%5Cfrac%7By1%2By2%7D%7B2%7D%29)
substitute the values
![M=(\frac{-2-2}{2},\frac{5-1}{2})](https://tex.z-dn.net/?f=M%3D%28%5Cfrac%7B-2-2%7D%7B2%7D%2C%5Cfrac%7B5-1%7D%7B2%7D%29)
![M_A_B=(-2,2)](https://tex.z-dn.net/?f=M_A_B%3D%28-2%2C2%29)
step 2
Find the equation of the line perpendicular to the segment AB that passes through the point (-2,2)
Is a horizontal line (parallel to the x-axis)
-----> equation A
step 3
Find the midpoint BC
The formula to calculate the midpoint between two points is equal to
![M=(\frac{x1+x2}{2},\frac{y1+y2}{2})](https://tex.z-dn.net/?f=M%3D%28%5Cfrac%7Bx1%2Bx2%7D%7B2%7D%2C%5Cfrac%7By1%2By2%7D%7B2%7D%29)
substitute the values
![M=(\frac{-2+8}{2},\frac{-1-1}{2})](https://tex.z-dn.net/?f=M%3D%28%5Cfrac%7B-2%2B8%7D%7B2%7D%2C%5Cfrac%7B-1-1%7D%7B2%7D%29)
![M_B_C=(3,-1)](https://tex.z-dn.net/?f=M_B_C%3D%283%2C-1%29)
step 4
Find the equation of the line perpendicular to the segment BC that passes through the point (3,-1)
Is a vertical line (parallel to the y-axis)
-----> equation B
step 5
Find the circumcenter
The circumcenter is the intersection point between the equation A and equation B
-----> equation A
-----> equation B
The intersection point is (3,2)
therefore
The coordinates of the circumcenter of this triangle are (3,2)