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77julia77 [94]
3 years ago
12

Help me ASAP Estimate the measure of ∠DBC.

Mathematics
1 answer:
maks197457 [2]3 years ago
3 0

Answer:

135°

Step-by-step explanation:

Considering it's estimation, there isn't too much of an explanation, but here you go anyways.

A straight angle is equal to 180°. DBE is a straight angle.

DBC and CBE added together appear to be 180° (supplementary).

We are trying to find DBC. An obtuse angle has to be over 90°, which in this case DBC clearly is over 90°. From that you can conclude it isn't any of the first 3, so it's D. 135°

hope this helps and give brainliest if I am epic blah blah blah ;)

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Can someone please help me I’ll give brilliant thingy
cricket20 [7]

Answer:

Yes, the shapes are similar. Note, the angles are equivalent and the sides are scales of each other satisfying the requirements for similarly.

Step-by-step explanation:

For a shape to be similar there are two conditions that must be met. (1) Must have equivalent angles (2) Sides must be related by a scalar.

In the two triangles presented, the first condition is met since each triangle has three angles, 90-53-37.

To test if the sides are scalar, each side must be related to a corresponding side of the other triangle with the same scalar.

9/6 = 3/2

12/8 = 3/2

15/10 = 3/2

Alternatively:

6/9 = 2/3

8/12 = 2/3

10/15 = 2/3

Since the relationship of the sides is the scalar 3/2 (Alternatively 2/3), then we can say the triangles meet the second condition.

Given that both conditions are satisfied, then we can say these triangles are similar.

Note, this is a "special case" right triangle commonly referred to as a 3-4-5 right triangle.

Cheers.

8 0
2 years ago
Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.
leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

12x-5y+14=0 \\ 12x-5y-14=0

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1

\Rightarrow 12h-5k-1=\pm 13

\Rightarrow 12h-5k=\pm 14

\Rightarrow 12h-5k=14,\ 12h-5k=-14

\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0

\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0
3 years ago
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Answer:

m=2y-3

Step-by-step explanation:

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2 years ago
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To work out the decrease, do original amount - new amount and then take that answer and divide it by the original amount, and then multiply by 100.

So you would do:

36.24 - 30.80 = 5.44
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Answer:

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