Answer:
Correct option is
B
5 liters of CH
4
(g)NO
2
at STP
No. of molecules=
22.4
5
mol=
22.4
5
×N
A
molecules
A) 5ℊ of H
2
(g)
No. of moles=
2
5
mol=
2
5
×N
A
molecules
B) 5l of CH
4
(g)
No. of moles of CH
4
=
22.4
5
mol=
22.4
5
N
A
molecules
C) 5 mol of O
2
=5N
A
O
2
molecules
D) 5×10
23
molecules of CO
2
(g)
Molecules of 5l NO
2
(g) at STP=5l of CH
4
(g) molecules at STP
Therefore, option B is correct.
Percentage
by mass is the amount in mass of a component in a mixture per 100 unit of mass of the total
mixture. Percentage by mass is the same as %w/w. In order to determine this value, we need to know the mass of the substance in question and the total mass of the sample. In this case, we have to know the mass of Fe by doing certain calculations. Then, we divide this value by the total mass given of the ore, 4.05 g and multiply by 100%. It should be expressed as follows:
Percent by mass = mass of Fe in ore / 4.05 g ore sample x 100
However, the question is lacking some information so we cannot really specify the answer.
Answer:
4%
Explanation:
the answer is 4% , hope this help
For a gas containing 80% CH4 and 20% He is sent through a quart diffusion tube, the composition is mathematically given as
%He=12.5%
%CH4=87.5%
<h3>What is the
composition of the waste gas if 100 kg moles of gas are processed per minute?</h3>
Generally, the equation for the Material balance is mathematically given as
F=R+W
Therefore
100=0.20*1000+W
W=80kmol/min
In conclusion, waste gas compose
2.0/100*100=50/100*20+%*80
Hence
%He=12.5%
%CH4=87.5%
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