P=2(W + L)
p= 2W + 2L
98=2W + 2(6W)
98=2W + 12W
98=W
98/14=14W/14
W=7
L= 6W
L = 6(7)
L= 42
CHECK
p=2(7 +42)
p=2(49)
p= 98
Area of a rectangle = W X L
Area of a rectangle = 7 X 42
Area of a rectangle = 294
Answer:
0.75
Step-by-step explanation:
Answer:
I think you can write like this:
5 x (5+2+4)
OR
5 x 11
Step-by-step explanation:
My own knowladge
Hope it helps
Put a thanks
Thank you
Answer:
Option (B)
Step-by-step explanation:
To calculate the distance between C2 and SW1 we will use the formula of distance between two points
and
.
d = 
Coordinates representing positions of C2 and SW1 are (2, 2) and (-6, -7) respectively.
By substituting these coordinates in the formula,
Distance between these points = 
= 
=
units
Therefore, Option (B) will be the correct option.
So to put them in intervals of 5 you would have:
70-74
75-79
80-84
85-89
90-94
95-99
In these intervals you would have:
70-74: 72
75-79: 78
80-84: 81
85-89: 86, 86, 87
90-94: 92, 92, 92
95-99: 98
The second interval is 75-79 where there is only one number. Therefore the frequency will be 1.
The correct answer is A. Hope this helps! :)