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3 years ago

Solve the inequality 0 > –3x – 2x.

Mathematics

1 answer:

Helga [31]3 years ago

6 0

Hey!

Hope this helps...

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This really depends on what the question asks, because if you substitute 0 for x, the equation comes to 0 > 0 (which is a logical error), if you substitute 1 for x, the equation comes to 0 > -5 (which is the correct answer). If you substitute -28 for x, you get 0 > 28 (and we know 28 will always be greater than 0, but 0 will never be greater than any positive number), this is the same if you were to substitute -36 for x, you get 0 > 36

So the correct answer is D.) x > 1

because you get 0 > -5 (when you plug in 1 for x), and 0 will always be greater than any given negative number...

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One more thing, this question is asking you to MAKE IT TRUE, IF it said 0 ≥ -3x - 2x... THAN A, B, and C would be correct, OR IF it said 0 ≤ -3x - 2x... THAN B and D would be correct, BUT because it only says 0 > -3x - 2x... THAN ONLY D is correct...

With a simple change of signs, you can dramatically change the answer to this equation

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► 00:00

Viefleur [7K]

Answer:

Proof

Step-by-step explanation:

PROOF can be said to be logical mathematical argument in which every statement of fact is supported by a reason

due to the fact mathematical proof is an inferential argument for a mathematical statement because it help to shows that the assumptions stated logically guarantee and enables the conclusion.

Therefore Proofs can be said to be an examples of exhaustive deductive reasoning because they tend to often establish logical certainty which can be differentiated from empirical arguments which inturn help to establish reasonable and effectively expectation as well as employ logic expressed in mathematical symbols which is why proofs are often written in terms of rigorous informal logic

7 0

3 years ago

What is 7P4 A: 28 B: 35 C: 210 D: 840

Semmy [17]

Answer:

Step-by-step explanation:

using the definition of n $P_{r}$ = $\frac{n!}{(n-r)!}$

where n! = n(n- 1)(n - 2)......× 3 × 2 × 1

here n = 7 and r = 4, hence

7 $P_{4}$

= $\frac{7!}{3!}$

= $\frac{7(6)(5)(4)(3)(2)(1)}{3(2)(1)}$ ← cancel 3 × 2 × 1 leaving

7 $P_{4}$ = 7 × 6 × 5 × 4 = 840 → D

4 0

3 years ago

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Consider the function below. f(x)= x^3 + 2x^2 - x - 2 plot the x and y intercepts of the function

dimulka [17.4K]

In the Figure below is shown the graph of this function. We have the following function:

$f(x)=x^3+2x^2-x-2$

The $y-intercept$ occurs when $x=0$ , so:

$f(0)=(0)^3+2(0)^2-(0)-2=-2$

Therefore, the $y-intercept$ is the given by the point:

$\boxed{(0,-2)}$

From the figure we have three $x-intercepts$ :

$\boxed{P_{1}(-2,0)} \\ \boxed{P_{2}(-1,0)} \\ \boxed{P_{3}(1,0)}$

So, the $x-intercepts$ occur when $y=0$ . Thus, proving this:

$f(x)=x^3+2x^2-x-2 \\ \\ For \ P_{1}:\\ If \ x=-2, \ y=(-2)^3+2(-2)^2-(-2)-2=0 \\ \\ For \ P_{2}:\\ If \ x=-1, \ y=(-1)^3+2(-1)^2-(-1)-2=0 \\ \\ For \ P_{3}:\\ If \ x=1, \ y=(1)^3+2(1)^2-(1)-2=0$

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3 years ago

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. Una persona desea realizar una pintura para su próxima exposición en donde esta tenga tres colores fluorescentes y dos colores

ycow [4]

Answer: B. 350.

Step-by-step explanation:

Given: Total number of fluorescent colors = 7

Total number of pastel colors = 5

Since , he want three fluorescent colors and two pastel colors.

Number of ways to select r things out of n things = $^nC_r=\dfrac{n!}{r!(n-r)!}$

Number of ways to choose colors = $^7C_3\times\ ^5C_2$

$=\dfrac{7!}{3!4!}\times\dfrac{5!}{2!3!}\\\\=\dfrac{7\times6\times5\times4!}{3\times2\times1\times4!}\times\dfrac{5\times4\times3!}{2\times3!}\\\\=350$

Hence, the correct option is B. 350.

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3 years ago

A petting zoo owner is building an enclosure for his farm animals. He needs 353 feet of fencing. The supply store sells fencing

jolli1 [7]

353/12 =29.41. But will have to round up to 30 so the answer is 30

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