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3 years ago

Solve the inequality 0 > –3x – 2x.

Mathematics

1 answer:

Helga [31]3 years ago

6 0

Hey!

Hope this helps...

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This really depends on what the question asks, because if you substitute 0 for x, the equation comes to 0 > 0 (which is a logical error), if you substitute 1 for x, the equation comes to 0 > -5 (which is the correct answer). If you substitute -28 for x, you get 0 > 28 (and we know 28 will always be greater than 0, but 0 will never be greater than any positive number), this is the same if you were to substitute -36 for x, you get 0 > 36

So the correct answer is D.) x > 1

because you get 0 > -5 (when you plug in 1 for x), and 0 will always be greater than any given negative number...

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One more thing, this question is asking you to MAKE IT TRUE, IF it said 0 ≥ -3x - 2x... THAN A, B, and C would be correct, OR IF it said 0 ≤ -3x - 2x... THAN B and D would be correct, BUT because it only says 0 > -3x - 2x... THAN ONLY D is correct...

With a simple change of signs, you can dramatically change the answer to this equation

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What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

Sunny_sXe [5.5K]

Answer:

First option is the correct option.

Step-by-step explanation:

$\frac{2x + 5}{ {x}^{2} - 3x } - \frac{3x + 5}{ {x}^{3} - 9x } - \frac{x + 1}{ {x}^{2} - 9 }$

Factor out X from the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x( {x}^{2} - 9)} - \frac{x + 1}{ {x}^{2} - 9}$

Using ${a}^{2} - {b}^{2} = (a - b)(a + b)$ , factor the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x(x - 3)(x + 3) } - \frac{x + 1}{(x - 3)(x + 3)}$

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

$\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}$

Multiply the parentheses

$\frac{2 {x}^{2} + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}$

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)}$

Distribute -x through the parentheses

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x }{x(x - 3)(x + 3)}$

Using ${a}^{2} - {b}^{2} = (a + b)(a - b)$ , simplify the product

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x}{x( {x}^{2} - 9)}$

Collect like terms

$\frac{ {x}^{2} + 7x + 15 - 5}{x( {x}^{2} - 9)}$

Subtract the numbers

$\frac{ {x}^{2} + 7x + 10}{ x({x}^{2} - 9)}$

Distribute x through the parentheses

$\frac{ {x}^{2} + 7x + 10}{ {x}^{3} - 9x}$

Write 7x as a sum

$\frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x }$

Factor out X from the expression

$\frac{x(x + 5) + 2x + 10}{ {x}^{3} - 9x}$

Factor out 2 from the expression

$\frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x }$

Factor out x + 5 from the expression

$\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }$

Hope this helps...

Best regards!!

6 0

3 years ago

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What is the value of g(9)?

ryzh [129]

I think B should be the answer

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3 years ago

How do you simplify 8+(9t+4)

IrinaVladis [17]

8+(9t+4)
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3 0

3 years ago

for every girl taking classes at the martial arts schools there are 3 boys who are taking classes at the school. if there are 23

Yuliya22 [10]

You have to be very careful how you set this up. For every girl (who counts as 1) there are 3 boys (who count as 3). The total number in the proportion is 3 + 1 =4. You are given a total, but that is both boys and girls. That's why you need the 4.

3/4 = x / 236 Cross multiply

4x = 3 * 236

4x = 708 Divide by 4

x = 708/4

x = 177

There are 177 boys at the school and 236 - 177 = 59 girls.

3 0

3 years ago

URGENTS PLLLLLSSSSSSSSS

Arlecino [84]

Just divide 300 by 4 since 25% is 1/4
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5 0

4 years ago

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