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Mars2501 [29]
3 years ago
15

(2n + 4) + 6 = –9 + 4(2n + 1)

Mathematics
2 answers:
Flauer [41]3 years ago
6 0
N = 2.5

2n + 10 = -9 + 8n + 4
2n + 10 = -5 + 8n
15 = 6n
n = 15/6
sattari [20]3 years ago
4 0

Answer:

n=2.5

Step-by-step explanation:

(2n+4)+6=-9+4(2n+1)

Expand parentheses:

2n+10=-9+8n+4

Combine like terms:

15=6n

Divide both sides by 6:

n=2.5

Hope this helps!

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Rasek [7]
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8 0
4 years ago
27x + 24y= 4.5<br><br> 1.5x + y =0.225
Goryan [66]

Answer:

x = 0.1, y = 0.075

Step-by-step explanation:

Given the 2 equations

27x + 24y = 4.5 → (1)

1.5x + y = 0.225 → (2)

Multiplying (2) by - 24 and adding to (1) will eliminate the y- term

- 36x - 24y = - 5.4 → (3)

Add (1) and (3) term by term to eliminate y

- 9x = - 0.9 ( divide both sides by - 9 )

x = 0.1

Substitute x = 0.1 into either of the 2 equations and solve for y

Substituting into (2)

1.5(0.1) + y = 0.225

0.15 + y = 0.225 ( subtract 0.15 from both sides )

y = 0.075

3 0
3 years ago
Read 2 more answers
Find the solution of the given initial value problems in explicit form. Determine the interval where the solutions are defined.
natali 33 [55]

Answer:

The solution of the given initial value problems in explicit form is y=x-x^2-2  and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

y'=1-2x

It can be written as

\frac{dy}{dx}=1-2x

Use variable separable method to solve this differential equation.

dy=(1-2x)dx

Integrate both the sides.

\int dy=\int (1-2x)dx

y=x-2(\frac{x^2}{2})+C                  [\because \int x^n=\frac{x^{n+1}}{n+1}]

y=x-x^2+C              ... (1)

It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

-2=1-(1)^2+C

-2=1-1+C

-2=C

The value of C is -2. Substitute C=-2 in equation (1).

y=x-x^2-2

Therefore the solution of the given initial value problems in explicit form is y=x-x^2-2 .

The solution is quadratic function, so it is defined for all real values.

Therefore the solutions are defined for all real numbers.

4 0
3 years ago
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