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3 years ago

A musician plans to perform 4 selections. In how many ways can she arrange the musical selections?

Mathematics

2 answers:

Y_Kistochka [10]3 years ago

8 0

The musician can arrange the musical selections 24 times. :)

Maru [420]3 years ago

3 0

Answer: There are 24 ways to arrange the musical selection.

Step-by-step explanation:

Since we have given that

Total number of selections that musicians plans to perform = 4

We need to find the number of arrangement that she can arrange the musical selections.

Since we know that for arrangements we use "Fundamental theorem of counting".

So, Number of ways that she can arrange the musical selections is

$4!\\\\=4\times 3\times 2\times 1\\\\=24$

Hence, there are 24 ways to arrange the musical selection.

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75,000 people went to watch the Huston Dynamos play Los Angeles Galaxy in the US Open final Cup At half time, Huston Dynamos wer

alexandr1967 [171]

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3 years ago

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olga_2 [115]

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2 years ago

what is the common ratio for the geometric sequence below, written as a fraction? 768, 480, 300, 187.5, …

Crazy boy [7]

Let

$a1=768\\a2=480\\a3=300\\a4=187.5$

Step $1$

Find $\frac{a2}{a1}$

$\frac{a2}{a1} =\frac{480}{768}$

Divide by $96$ numerator and denominator

$\frac{480}{768} =\frac{\frac{480}{96}}{\frac{768}{96}} \\ \\ \frac{480}{768}=\frac{5}{8}$

$a2=a1*\frac{5}{8}$

Step $2$

Find $\frac{a3}{a2}$

$\frac{a3}{a2} =\frac{300}{480}$

Divide by $60$ numerator and denominator

$\frac{300}{480} =\frac{\frac{300}{60}}{\frac{480}{60}} \\ \\ \frac{300}{480}=\frac{5}{8}$

$a3=a2*\frac{5}{8}$

Step $3$

Find $\frac{a4}{a3}$

$a4=187.5 \\ a4=187\frac{1}{2} \\ \\ a4=\frac{375}{2}$

$\frac{a4}{a3} =\frac{\frac{375}{2}}{300} \\ \\ \frac{a4}{a3} =\frac{375}{600}$

Divide by $75$ numerator and denominator

$\frac{375}{600} =\frac{\frac{375}{75}}{\frac{600}{75}} \\ \\ \frac{375}{600}=\frac{5}{8}$

$a4=a3*\frac{5}{8}$

In this problem

The geometric sequence formula is equal to

$a(n+1)=a(n)*\frac{5}{8}\\$

For $n\geq 1$

therefore

the answer is

the common ratio for the geometric sequence above is $\frac{5}{8}$

6 0

3 years ago

Read 2 more answers

Whitch three capital letters have rotational symmetry but do not have line symmetry

deff fn [24]

First you want to figure out what exactly it is you are looking for. We are looking for "capital letters that have rotational symmetry but do not have line symmetry"

So:
1. Must have rotational symmetry.
This means that if we rotate the capital letter 180 deg, either clockwise or counterclockwise, it will still look the same

2. Must not have line symmetry.
If an object has line symmetry, it means that if you draw a line down the middle (in any way), it will be symmetrical on both sides. We need capital letters that do not fit that condition.

Now we look at all capital letters.
We find that H, I, N,O, S, X, and Z are all rotationally symmetrical. Think about it. If you rotate them, they still look the same.

But, we have to make sure they do not have line symmetry. If we draw a line right down the middle of H, I, O and X (**note, the have multiple lines of symmetry), they are symmetrical on both sides of the line.

Now we are left with N, S, and Z

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3 years ago

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The measured length is 250 ft. The actual length is 246.9 ft. Find the percent error.

Marta_Voda [28]

Percent error = 1.2556%

Steps:
Percent Error =
Vobserved - Vtrue
Vtrue
=
250 - 246.9
246.9
=
3.1
246.9
= 1.2555690562981%

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3 years ago