Answer: see proof below
<u>Step-by-step explanation:</u>

Use the following Identities:
sec Ф = 1/cos Ф
cos² Ф + sin² Ф = 1
<u>Proof LHS → RHS</u>






Answer:
63
Step-by-step explanation:
9x7=(10x7)-1x(7)
=70-7
=63
Answer:
y=1/3x+2
Step-by-step explanation:
Answer:
True.
Step-by-step explanation:
You're assuming that this data set represents all of Mrs. Hassaan's pupils. Certain students could be missing from the histogram - for instance, there could be one or two students who missed the test, but for certain reasons will be taking a make-up exam. Their grade would not be recording in this data set, but they still contribute to the class size, and so would be unaccounted for here.