◆ Define the variables:
Let the calorie content of Candy A = a
and the calorie content of Candy B = b
◆ Form the equations:
One bar of candy A and two bars of candy B have 774 calories. Thus:
a + 2b = 774
Two bars of candy A and one bar of candy B contains 786 calories
2a + b = 786
◆ Solve the equations:
From first equation,
a + 2b = 774
=> a = 774 - 2b
Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie
◆ Find caloric content:
Caloric content of candy B = 254 calorie
Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
Answer:
(3,4)
Step-by-step explanation:
first you're going to solve the equation -2x
your equation should now be:
next you're going to substitute the given value of -2x into the equation
so your equation should now be:
next you're going to solve the equation for y
equation should now be: y=4
than you're going to substitute the given value of y into the equation ×
then you're going to solve the equation for x
your equation should now be: x=3
then the possible solution of the system is the order pair: (x,y)=(3,4)
Answer:
a equal to c 25 b greater than
Step-by-step explanation:
The degree is the highest power so
I) 2
Ii) 4
Convert the fraction 3/4 to decimal form to get 3/4 = 0.75
To factor out 3/4, we divide each term by 3/4 or 0.75
It might be easier to divide by 0.75 to avoid two division symbols
So (3/4)z+6 = 0.75z+6
Divide each term (0.75z and 6) by 0.75 which is what we want to factor out
0.75z/0.75 = z
6/0.75 = 8
Therefore,
0.75z+6 = 0.75*(z+8)
Note how we can distribute the 0.75 back through to each term inside (z and 8) and we'll end up with 0.75z+6 again.
The answer in fraction form is
which is 3/4 outside the parenthesis multiplied by the group (z+8)