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2 years ago

What is the distance from the point (a, −b, −4) to the origin?

Mathematics

1 answer:

laiz [17]2 years ago

6 0

Answer:

$\sqrt{a^2+b^2+16}$

Step-by-step explanation:

The distance (d) between two points in 3 dimensions is ...

d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)

Then the distance between (a, -b, -4) and (0, 0, 0) is ...

d = √((a -0)² +(-b -0)² +(-4 -0)²)

= √(a² +b² +16)

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F(x) = 23 – 22 g(x) = 4x + 5

Mandarinka [93]

Answer:

23-22=1

5 times 4=20

Step-by-step explanation:

7 0

3 years ago

Solve for x 5(x+1)=4(x+8)

joja [24]

Answer:

x=27

Step-by-step explanation:

expanding the above expression we get

5x+5=4x+32

grouping numbers with coefficient of x at the left side and constant at the right side we get

5x-4x=32-5

x=27

8 0

3 years ago

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If a turtle walk 2 yards then 10 in then 3 ft how many inches did it walk in all

ki77a [65]

Answer:

118

Step-by-step explanation:

2 yards=72 in

10inches=10inches

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2 years ago

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There are currently 18 pit bulls at the pound. Of the 18 pit bulls, four have attacked another dog in the last year. Joe, a memb

laila [671]

Answer: 0.7748

Step-by-step explanation:

Given : Number of bit bulls at the pound = 18

Number of pit bulls have attacked another dog in the last year =4

The proportion of pit bulls have attacked another dog in the last year: $p=\dfrac{4}{18}\approx0.22$

Number of the pit bulls selected = 6

The probability of that none of the pit bulls in Joe's group attacked another dog last year : $P(0)=(1-0.22)^6=0.225199600704\approx0.2252$

By using binomial , the probability that at least one of the pit bulls in Joe's group attacked another dog last year is given by :-

$P(x\geq 1)=1-P(x$

Hence, the required probability = 0.7748

3 0

2 years ago

What is the value of (-3+3i)+(-2+3i)? -5-6i -5+6i 5+6i 5-6i

Luda [366]

Step-by-step explanation:

-3+3i-2+3i

-5+6i

Hope that helps you

8 0

2 years ago