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ycow [4]
3 years ago
10

What is the pH of a 2.2 M solution of HClO4?

Chemistry
1 answer:
agasfer [191]3 years ago
7 0
Since HClO4 is a strong acid it will completely dissociate in solution. 

HClO4 + H2O --> H3O+ + ClO4-

Therefore, your concentration of HClO4 will be equal to your amount of H3O+, the conjugate acid in solution. 

The Ka expression is as follows:

Ka= [H3O+][ClO4-] / [HClO4] 

So you know that -log [H3O+] gets you pH, so just plug in [2.2] as your concentration of H3O+ and your answer should be -.34 pH


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SE LES DARA EL NUMERO ATOMICO DEBERAN REALIZAR LA CONFIGURACION ELECTRONICA ESCRIBE SU NOMBRE SIMBOLO Y UBICACION EN LA TABLA PE
IrinaK [193]

Answer:

Zinc, Cerio, Talio, Cloro y Criptón.

Explicación:

El zinc es el elemento que tiene el número atómico 30 y su símbolo es Zn. Se encuentra en el grupo 2B de la tabla periódica. El cerio es el elemento que tiene el número atómico 58 y su símbolo es Ce. Se encuentra en el grupo de lantánidos de la tabla periódica. El talio es el elemento que tiene el número atómico 81 y su símbolo es Tl. Se encuentra en el tercer grupo de la tabla periódica. El cloro es el elemento que tiene el número atómico 17 y su símbolo es Cl. Se encuentra en el séptimo grupo de la tabla periódica. El criptón es el elemento que tiene el número atómico 36 y su símbolo es Kr. Se encuentra en el grupo de gases nobles, es decir, en la tabla periódica del octavo grupo.

4 0
3 years ago
8) Determine whether mixing each pair of the following results in a buffera. 100.0 mL of 0.10 M NH3 with 100.0 mL of 0.15 MNH4Cl
Marina86 [1]

Answer:

a. 100.0 mL of 0.10 M NH₃ with 100.0 mL of 0.15 M NH₄Cl.

c. 50.0 mL of 0.15 M HF with 20.0 mL of 0.15 M NaOH.

Explanation:

A buffer system is formed in 1 of 2 ways:

  • A weak acid and its conjugate base.
  • A weak base and its conjugate acid.

Determine whether mixing each pair of the following results in a buffer.

a. 100.0 mL of 0.10 M NH₃ with 100.0 mL of 0.15 M NH₄Cl.

YES. NH₃ is a weak base and NH₄⁺ (from NH₄Cl ) is its conjugate base.

b. 50.0 mL of 0.10 M HCl with 35.0 mL of 0.150 M NaOH.

NO. HCl is a strong acid and NaOH is a strong base.

c. 50.0 mL of 0.15 M HF with 20.0 mL of 0.15 M NaOH.

YES. HF is a weak acid and it reacts with NaOH to form NaF, which contains F⁻ (its conjugate base).

d. 175.0 mL of 0.10 M NH₃ with 150.0 mL of 0.12 M NaOH.

NO. Both are bases.

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