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3 years ago

A polar bear migrates north during winter to hunt for its food on sea ice. The daily

Mathematics

1 answer:

Olegator [25]3 years ago

8 0

Answer:

-4 degrees

Step-by-step explanation:

Starting at 2 degrees, you need to subract 6 since 200 km= 6 degrees and it decreases.

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Find the area of the shape above

kirill115 [55]

Answer:

625 cm^2

Step-by-step explanation:

Break it into a rectangle on the bottom and a triangle on top

rectangle area = 50 x 8 = 400 cm^2

triangle area = 1/2 b * h = 1/2 * 50 * 9 = 225 cm^2

added together = 625 cm^2

6 0

2 years ago

In the problem 4 x 12 = 48 which numbers are the factors

Volgvan

C 4and 12 are the factors of 48

3 0

3 years ago

Read 2 more answers

g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for h:

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for h.

$\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r} \end{aligned}$

Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0

3 years ago

PLEASE HELP LAST TWO QUESTIONS, I USED ALL MY POINTS TO POST THIS PLEASE PLEASE PLEASE HELP VERY IMPORTANT

Radda [10]

10.
if we were to subsitute the points and graph the equation we would notice that the shape is the same for both: a 45 degree angle line that goes upleft and up right
the graph of y=|x| looks like a right angle corner that is facing up that is ballancing on the point (0,0)
the graph of y=|x|-4 is the same except that the graph is shifter 4 units to the right ie. the point ofo the graph/rightangle is on point (4,0)

14.
slope intercept form which is y=mx+b
m=slope b=y intercept
m=4/3
y=4/3x+b
one given solution/point is (9,-1)
one solution is x=9 and y=-1 so subsitute and solve fo b
-1=4/3(9)+b
-1=36/3+b
-1=12+b
subtract 12 from both sides
-11=b
the equation si y=4/3x-11
see which one converts to the correct form
after trial and error we find that y-1=4/3(x-9) is the answer

8 0

3 years ago

Avery is programming her calculator to make a graph of the letter v. The points she uses for the left side of the letter are lis

Gnoma [55]

What is the question I don’t understand

6 0

4 years ago

Read 2 more answers