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natulia [17]
3 years ago
12

(x+5)(x+1)+(x+5)(x+8)

Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer:

2x² + 19x + 45

Step-by-step explanation:

(x + 5)(x + 1) + (x + 5)(x + 8) ← expand both sets of factors using FOIL

= x² + 6x + 5 + x² + 13x + 40 ← collect like terms

= 2x² + 19x + 45

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Answer the following questions about the function whose derivative is f primef′​(x)equals=x Superscript negative three fifths Ba
Elden [556K]

Answer:

(a) The critical points of f are x=0 and x=3.

(b)f is decreasing on (0,3) and f is decreasing on (3,\infty).

(c) Therefore the local minimum of f is at x=3

Step-by-step explanation:

Given function is

f'(x)= x^{-\frac35}(x-3)

(a)

To find the critical point set f'(x)=0

\therefore  x^{-\frac35}(x-3)=0

\Rightarrow x=0,3

The critical points of f are 0,3.

(b)

The interval are (0,3) and (3,\infty).

To find the increasing or decreasing, taking two points one point from the interval (0,3) and another point (3,\infty).

Assume 1 and 4.

Now f'(1)=(1)^{-\frac35}(1-3)

and f'(4)=(4)^{-\frac35}(4-3)>0

Since 1∈(0,3) , f'(x)<0  and 4∈(3,\infty) , f'(x)>0

∴f is decreasing on (0,3) and f is decreasing on (3,\infty).

(c)

f'(x)= x^{-\frac35}(x-3)

Differentiating with respect to x

f''(x)=-\frac35x^{-\frac 85}(x-3)+x^{-\frac35}

Now

f''(0)=-\frac35(0)^{-\frac 85}(0-3)+(0)^{-\frac35}=0

and

f''(3)=-\frac35(3)^{-\frac 85}(3-3)+3^{-\frac35}

        =0.517>0

Since f''(x)>0 at x=3

Therefore the local minimum of f is at x=3

8 0
3 years ago
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