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natulia [17]
2 years ago
12

(x+5)(x+1)+(x+5)(x+8)

Mathematics
1 answer:
gtnhenbr [62]2 years ago
5 0

Answer:

2x² + 19x + 45

Step-by-step explanation:

(x + 5)(x + 1) + (x + 5)(x + 8) ← expand both sets of factors using FOIL

= x² + 6x + 5 + x² + 13x + 40 ← collect like terms

= 2x² + 19x + 45

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50 points
mixer [17]

Answer:

c = -13.78.

Step-by-step explanation:

21.2x + c  ≡ 5.3(4x - 2.6)

21.2x + c  ≡ 21.2x - 13.78

Equating constant terms:

c = -13.78.

7 0
2 years ago
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1. 1 +2r =<br><br><br> 2. 12 = 18 - d<br><br><br> 3. 5b + 10 = 30
seropon [69]

Answer:

1. r=anything

2. d=6

3. b=4

Step-by-step explanation:

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2 years ago
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5y + 4 = 4y +5<br> Halp plz
shepuryov [24]

Answer:

y=1

Step-by-step explanation:

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8 0
3 years ago
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In the problem solving process, the final step is to try to ______.
Valentin [98]
The final steps is to review your results.

This means that you have to check if the results meet the original requirements or statements.

Ideally, you should try to solve the same problem by a second method, and/or you should substitute the results into the given relationships given in the problem statement to chek coherence of your results.

Then the answer is option b.
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3 years ago
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The function f(x) = −x^2 − 5x + 50 shows the relationship between the vertical distance of a diver from a pool's surface f(x), i
pychu [463]
Set the function to equal zero:

-x^2 - 5x + 50 = 0

To find the zeros, or solutions, to this problem, we will use the quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Plug the values into the equation:

a = -1, b = -5, c = 50

x=\frac{5\pm\sqrt{-5^2-4(-1)(50)}}{2(-1)}

x=\frac{5\pm\sqrt{25+200}}{-2}

x=\frac{5\pm15}{-2}

Solve for both plus and minus:

\frac{5 + 15}{-2} = \frac{20}{-2} = -10

\frac{5 - 15}{-2} = \frac{-10}{-2} = 5

x = -10, x = 5

The question cannot use a negative value for x, as the diver cannot dive a negative distance from the board.

The answer is '<span>x = 5; the diver hits the water 5 feet away horizontally from the board', because x represents the horizontal distance away from the board.</span>
4 0
3 years ago
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