Answer:
The given functions are
The sine function has a standard period of 
by definition. However, this might change if we use a factor as coefficient of the x-varible, but in this case we don't have that.
Therefore, the period of both trigonometric functions is .
Now, the images of each function is the y-variable set values that defines each function.
So, the function has an image defined by the set ![[-3,5]](https://tex.z-dn.net/?f=%5B-3%2C5%5D)
. It's impotant to notice that the range of a standard function is [-1,1], however, in this case, the function was shifted 1 unit up and it was streched by a factor of 4, that's why the standard image changes to .
About the second function , the image set is ![[-2,2]](https://tex.z-dn.net/?f=%5B-2%2C2%5D)
, because the function was streched by a factor of 2.
Additionally, the image attached shows the graph of the given functions.
Step-by-step explanation:
Nnnnnnnnnnnn is a great way to get a new phone and I am not sure if you are interested in the position of the position and the position of the company and the company is a
Answer:
multiplying 2 then dividing
Step-by-step explanation:
The reciprocal of any number is the other number you must multiply it by to equal one. In this case it's 9/2
