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3 years ago

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Lo is leaving from work today at 6:15 p.m. She has errands to run before she meets her friends for dinner at 8 p.m. If it takes

Lo of an hour to run each errand, how many errands does she have time to run between work and dinner?

1 answer:

Nookie1986 [14]3 years ago

4 0

Answer:

1 errand

Step-by-step explanation:

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Sara weight 25 pound-more than amber if together they weight 205 what is the weight of sara ??

serg [7]

Let Sara weight =x+25
amber wiegh =x
x+25+x=205
x= 90
Sara weight is 90+25= 115

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3 years ago

HI can you help me with this problem?The quantity demanded x for a certain brand of MP3 players is 300 units when the unit price

Vlad [161]

The demand equation is P = -0.05x + 105

STEP - BY - STEP EXPLANATION

What to find?

<em>The demand equation.</em>

The following information is used to solve the problem.

If (x₁ , y₁) and (x₂, y₂) are any dinstinct points on a line a non-vertical line L, then the equation of the line that has a slope(m) and passes through the point (x₁ , y₁) is given by the formula below:

$y-y_1=_{}\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Assume p, be the unit price and x be the demand when the price is $p.

From the question given, when the unit price x = 300 units, the demand p = $90 and when the unit price x = 1300 units, the demand p = $40

This means the demand curve passes through the points (300, 90) and (1300, 40).

Assume the demand equation is linear, then the line of the equation passes through the points (300, 90) and (1300, 40).

Now;

y=p x₁ =300 y₁ = 90 x₂ = 1300 y₂=40

Substitute the values into the function and simplify.

$p-90=\frac{40-90}{1300-300}(x-300)$

Simplify the above.

$p-90=\frac{-50}{1000}(x-300)$ $p-90=-0.05(x-300)$

Open the parenthesis.

P- 90 = -0.05x + 15

Add 90 to both-side of the equation.

P = -0.05x + 15 + 90

P = -0.05x + 105

Hence, the demand function is P = -0.05x + 105

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1 year ago

What is the value of x and z

saw5 [17]

Z is 109 and x is 13

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3 years ago

14. BUS TRIP A bus leaves at 10 A.M. to take students on a field trip to a

k0ka [10]

The bus is 54.5 miles far from the site at the time of 11:30A.M as per the given information in the question.

<h3>What is the slope of a line?</h3>

The slope of a line indicates how steep it is. Slope is defined mathematically as "climb over run" (change in y divided by change in x).

It is assumed that a bus moving at a constant speed departs at 10 a.m. towards a historic location, is 100 miles away by 10:25 a.m., and is 65 miles away at 11:15 a.m.

We must create a point-slope equation that connects the distance from the place to the time in minutes after 10:00 a.m. Then, around 11:30 a.m., we need to figure out how far the bus is from the site.

A line's point-slope is y₂-y₁)=m(x₂-x₁)

Since x denotes the amount of minutes after 10:00 a.m., 10:25 a.m. is represented by x=25 and 11:15 a.m. by x=75.

At 10:25 a.m., a distance of 100 miles from the place is represented by 75.

The point represents a distance of 100 miles from the site at 10:25 a.m. The point represents a distance of 65 miles from the site at 11:15 a.m.

By substituting the points (25, 100) and (75, 65) into the slope formula and simplifying we get,

m=(y₂-y₁)/(x₂-x₁)

m=(65-100)/(75-25)

m=-35/50

m=-0.7

Now choose one of the points and substitute that point and the slope into the slope-point form

y₋y₁=m(x-x₁)

By choosing (x₁, y₁)=(25, 100)

By choosing (x₂, y₂)=(75, 65)

Since 11:30 A,M is 90 minutes after 10:00A.M

By substituting x=90 in the equation we get the value of y,

y-100= -0.7(90-25)

y-100= -0.7(65)

y-100 =-45.5

y= 54.5

Hence, the bus is 54.5 miles from the site at the time of 11:30 A.M

y-100= -0.7(x-25)

OR

y-65= -0.7(x-75)

The bus is 54.5 miles from the site at 11:30A.M.

To know more about slope of a line, visit:

brainly.com/question/28771374

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1 year ago

Peter put $8,000 into a savings account that pays 6% interest, compounded continuously. After five years, Peter will have $in th

Dmitrij [34]

We have to calculate the amount of money Peter will have in his account after 5 years. Formula for the amount after t years with interest compounded continuously : A = P * e^(r t ). We know that r = 0.06; t = 5; e = 2.71 and P = $8,000. A = 8,000 * 2.718^( 0.06 * 5 ) = 8,000 * 2,718^( 0.3 ) = 8,000 * 1.3488158 = 10,798.53. Answer:<span> B. $10,798.53. </span>

6 0

3 years ago