1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
storchak [24]
4 years ago
15

Help me please on #2

Physics
1 answer:
oksian1 [2.3K]4 years ago
7 0
It would be chemical weathering
You might be interested in
A box is pulled along a floor by a force of 3.0 N. The friction acting on the box is 1.0 N, as shown. How much kinetic energy do
Furkat [3]

Answer:

4 J

Explanation:

From the image attached, we can see 2 horizontal forces acting on the box albeit in opposite directions.

Now, the net force will be;

F_net = 3 - 1

F_net = 2 N

To move a distance of 2 metres, kinetic energy is;

K.E = Force × Distance = 2 × 2 = 4 J

7 0
3 years ago
A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 4.79 g coins stacked over the 28.8 cm mark, th
masha68 [24]

To solve the exercise, the key concept to be addressed is the Mass Center.

The center of mass of an object is measured as,

X_{cm} = \frac{\sum m_ix_i}{\sum m_i}

X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}

Our values are given by,

x_1 = 50cm

m_1 = ?

x_2 =28.8cm

m_2 = 4.79g

x_3 = 28.8cm

m_3 = 4.79g

X_{cm} = 38.4cm

Replacing the values in our previous equation we have,

X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}

38.4 = \frac{m_1(50)+2(28.8*4.79)}{m_1+2*4.79}

38.4(m_1+2*4.79)= m_1(50)+2(28.8*4.79)

38.4m_1 +367.872 = 50m_1+275.904

11.6m_1 = 91.968

m_1 = 7.928g

Therefore the mass of the meter stick is 7.928g

7 0
3 years ago
A pickup truck is traveling down the highway at a steady speed of 30.1 m/s. The truck has a drag coefficient of 0.45 and a cross
Sav [38]

Answer:

The energy that the truck lose to air resistance per hour is 87.47MJ

Explanation:

To solve this exercise it is necessary to compile the concepts of kinetic energy because of the drag force given in aerodynamic bodies. According to the theory we know that the drag force is defined by

F_D=\frac{1}{2}\rhoC_dAV^2

Our values are:

V=30.1m/s

C_d=0.45

A=3.3m^2

\rho=1.2kg/m^3

Replacing,

F_D=\frac{1}{2}(1.2)(0.45)(3.3)(30.1)^2

F_D=807.25N

We need calculate now the energy lost through a time T, then,

W = F_D d

But we know that d is equal to

d=vt

Where

v is the velocity and t the time. However the time is given in seconds but for this problem we need the time in hours, so,

W=(807.25N)(30.1m/s)(3600s/1hr)

W=87.47*10^6J (per hour)

Therefore the energy that the truck lose to air resistance per hour is 87.47MJ

4 0
3 years ago
A child and sled with a combined mass of 58.0 kg slide down a frictionless slope. If the sled starts from rest and has a speed o
erma4kov [3.2K]

Answer:

The height is  h = 0.5224 \ m

Explanation:

From the question we are told that

   The combined mass of the child and the sled is  m =  58.0 \  kg

    The  speed of the sled is  u = 3.20 \ m/s

Generally applying SOHCAHTOA on the slope which the combined mass is down from

   Here the length of the slope(L)  where the combined mass slides through  is the hypotenuses

   while the height(h) of the height of the slope is the opposite

Hence from SOHCAHTOA

      sin (\theta) =  \frac{h}{L}

=>   Lsin(\theta) = h

Generally from the kinematic equation we have that

   v^2  = u^2 + 2aL

Here the u  is the initial velocity of the combined mass which is zero since it started from rest

 and  a is the acceleration of the combined mass which is mathematically evaluated as

       a =  g * sin (\theta )

      v^2  = u^2 + 2 *  g * sin (\theta )L

=>   2Lsin(\theta ) =  \frac{v^2 - u^2 }{g}

=>   h = \frac{ v^2 - u^2}{2g}

=>   h = \frac{ 3.20^2 - 0^2}{2 * 9.8 }

=>   h = 0.5224 \ m

6 0
3 years ago
Baseball homerun hitters like to play in Denver, but<br> curveballpitchers do not. Why?
pishuonlain [190]

Answer:

Because of height and lower atmospheric pressure.

Explanation:

Atmospheric pressure affects aerodynamic drag, lower pressure means less drag. At the altitude of Denver the air has lower pressure, this allows baseball players to hit balls further away.

Another aerodynamic effect is the Magnus effect. This effect causes spinning objects to curve their flightpath, which is what curveball pitchers do. A lower atmospheric pressure decreases the curving of the ball's trajectory.

5 0
3 years ago
Other questions:
  • You are sitting in your car at rest at a traffic light with a bicyclist at rest next to you in the adjoining bicycle lane. As so
    8·1 answer
  • A flat circular mirror of radius 0.210 m is lying on the floor. Centered directly above the mirror, at a height of 0.660 m, is a
    10·1 answer
  • One of the main differences between the intaglio and the relief printing processes is that with intaglio the ink ________ the su
    15·1 answer
  • Frank and Lisa are analyzing the chart, which shows the speed at which light travels through different media. Frank says that li
    14·2 answers
  • Which factors affect friction between two solid surfaces?
    15·2 answers
  • Um chuveiro C e um forno de micro-ondas M são ligados, como não há circuito a seguir.
    12·1 answer
  • What is the force of a 24.52 kg Television dropped on Pluto (acceleration of 0.59 m/s2)
    5·1 answer
  • An explosion that destroys a massive star is called a
    14·1 answer
  • Light hitting a rough surface would most likely:
    12·1 answer
  • What must be the mass of a model rocket to develop an acceleration of 520m/s2 when subjected to a net force of 11.2N?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!