Transformation 3 should Tracy removed from the list. Chemical energy transforms into gravitational potential energy.
<h3> What is the law of conservation of energy?</h3>
According to the Law of Conservation of Energy, energy can neither be created nor destroyed, but it can be transferred from one form to another.
The total energy is the sum of all the energies present in the system. The potential energy in a system is due to its position in the system.
Transformations that occur as an engine runs to power a car is;
1. Chemical energy of fuel transforms into thermal energy.
2. Thermal energy transforms into electrical energy used to lighten the bulb in a car.
3. Thermal energy transforms into kinetic energy to help to run the car.
Chemical energy transforms into gravitational potential energy is the incorrect energy transformation.
Hence, transformation 3 should Tracy removed from the list.
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The distance d₁ it rises from rest while the engine is burning is given by
d₁ = d₀ + v₀t + (1/2)at²
d₁ = 0 + 0 + (1/2)·(29.4 m/s²)·(3.98 s)² = 232.85 m
So it gets to 232.85 m and then runs out of fuel. Its velocity v₁ at this point is given by
v₁ = v₀ + at = (29.4 m/s²)·(3.98 s) = 117 m/s
At this point, gravity begins to slow it down until it reaches its peak where its velocity v₂ is zero.
v₂² = v₁² + 2ad₂
where d₂ is the distance it rises until v=0
Since gravity is decelerating the rocket, a = -g, and we have
0² = (117 m/s)² + 2(-9.8 m/s²)d₂
0 = (117)² - (19.6)·d₂
0 = 13,689 - (19.6)·d₂
d₂ = 13,689/19.6 = 698.42 m
So the total height it rises is given by
d₁ + d₂ = 232.85 m + 698.42 m
= 931.27 m
Answer:
(a) 
(b) 
Given:
Time period of Pulsar, 
Equatorial radius, R = 15 Km = 15000 m
Spinning time, 
Solution:
(a) To calculate the value of the centripetal acceleration, 
on the surface of the equator, the force acting is given by the centripetal force:
(1)
where
(2)
Now, from (1) and (2):
(b) To calculate the tangential acceleration of the object :
The tangential acceleration of the object will remain constant and is given by the equation of motion as:
where
u = 
A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 
/sec .
Discharge rate = velocity * area
= velocity * depth * width
= 2 * 2 * 10 = 40 /sec
A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 /sec .
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