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Naily [24]
3 years ago
12

Um chuveiro C e um forno de micro-ondas M são ligados, como não há circuito a seguir.

Physics
1 answer:
uysha [10]3 years ago
3 0

Responder:

50A

Explicación:

Dado que el Um chuveiro y el microondas están conectados en paralelo, el mismo voltaje fluirá a través de ellos.

La potencia total consumida por ambos aparatos = 4800W + 1200W

La potencia total consumida por ambos aparatos = 6000W

Para obtener el I actual, usaremos la fórmula;

P = IV

6000 = 120I

Yo = 6000/120

Yo = 50 A

Por lo tanto, la medición de corriente del amperímetro ideal A será 50A

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Obtain the temp. at which the reading of Fahrenheit is double of that in Celsius scale.​
SVEN [57.7K]

Answer:

320 degrees fahrenheit and 160 degrees celcius

Explanation:

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7 0
3 years ago
Suppose a cyclist travels 15 kilometers during the first hour. Then the cyclist travels 33 kilometers during the next 2 hours. W
Natasha2012 [34]

Average speed  =  (total distance)  /  (total time to cover the distance)

                             =  (15 km + 33 km)  /  (1 hr + 2 hrs)

                             =      (48 km)          /    (3 hrs)

                             =                    (48/3)    km/hr

                             =                       16      km/hr .
7 0
3 years ago
20 POINTS MULTIPLE CHOICE
Shkiper50 [21]
If mass doubled and the force remained constant then the acceleration would also double

Hopes this helps
3 0
4 years ago
A nickel (5 cent coin) has a mass of 5.0 g. How many nickels are there in a stack of nickels with a mass of 10.0 kg?
Marrrta [24]

Answer:

2000 nickels

Explanation:

One way to solve proportionality problems, direct and inverse: the simple 3 rule.

If the relationship between the magnitudes is direct (when one magnitude increases so does the other), the simple direct rule of three must be applied.

On the contrary, if the relationship between the magnitudes is inverse (when one magnitude increases the other decreases) the rule of three simple inverse applies.

The simple 3 rule is an operation that helps us quickly solve proportionality problems, both direct and inverse.

To make a simple rule of three we need 3 data: two magnitudes proportional to each other, and a third magnitude. From these, we will find out the fourth term of proportionality.

In the simple three rule, therefore, the proportionality relationship between two known values ​​A and B is established, and knowing a third value C, a fourth value D is calculated.

A -> B

C -> D

Calculation

1 nickel --> 5 g

X? nickel --> 10000g

X = (10000 g * 1 nickel) / 5 g

X = 2000 nickels

7 0
3 years ago
A lowly high diver pushes off horizontally with a speed of 2.00 m/s from the platform edge 10.0 m above the surface of the water
VladimirAG [237]

Answer:

(a) 1.6m

(b) 6.86m

(c) 2.86s

Explanation:

This is a horizontal shooting problem, so we will use the following equations.

For horizontal distance x we use:

x(t)=x_{0}+v_{0}t

Where x(t) is the horizontal distance at a time t, x_{0} is the initial horizontal position which in this case will be zero: x_{0}=0. And v_{0} is the initial speed: v_{0}=2m/s

So to solve (a):

(a) At what horizontal distance from the edge is the diver 0.800 s after pushing off?

we have that the time is: t=0.8s so the horizontal distance is:

x(0.8)=(2m/s)(0.8s)1.6m

<u>The answer for (a) is 1.6m</u>

Now, to solve (b) we need the equation for vertical distance:

y(t)=y_{0}-\frac{1}{2}gt^2

Where y(t) is the vertical distance at a time t, y_{0} is the initial vertical distance: y_{0}=10m And g is the gravitational acceleration: g=9.81m/s^2 }

(b) At what vertical distance above the surface of the water is the diver just then?

The time is the same as in the last question: t=0.8s

y(0.8)=10m-\frac{1}{2}(9.81m/s^2)(0.8)^2

y(0.8)=10m-\frac{1}{2}(9.81m/s^2)(0.64s^2)

y(0.8)=10m-\frac{1}{2}(6.2784m)

y(0.8)=10m-(3.1392)

y(0.8)=6.86m

<u>the answer to (b) is 6.86m</u>

(c) At what horizontal distance from the edge does the diver strike the water?

To solve (c) we first need to know how long it took to reach the height of the water, that is, for what time y = 0

Using y(t)=y_{0}-\frac{1}{2}gt^2

if y(t)=0

0=10-\frac{1}{2}gt^2\\-10=-\frac{1}{2}gt^2\\20=gt^2\\\frac{20}{g}=t^2\\ \sqrt{\frac{20}{g}}=t

and since g=9.81m/s^2

t=\sqrt{\frac{20}{9.81} } =\sqrt{2.039}=1.43s

At t=1.43s the car hits the water, so the horizontal distance at that time is:

x(t)=x_{0}+v_{0}t

x(1.43)=(2m/s)(1.43s)=2.86m

<u>the answer to (c) is 2.86s</u>

6 0
3 years ago
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