Answer: 3, 5, 7
Step-by-step explanation:
There is a "trick" to determine divisibility by 3: if the sum of the digits is divisible by 3, the number is divisible by 3.
3 + 1 + 5 = 9 which is a multiple of 3, so 315 is divisible by 3.
It works for 9 also. since the sum of the digits is 9, 315 is divisible by 9.
Divisibility by 5: any number that has the units digit 5 or 0 is divisible by 5.
For 7, I just tried it 315÷7= 45
Only even numbers are divisible by 2.
If a 3-digit number is divisible by 11, the middle digit will be the sum of the first and last digits. (That is not the case for 315) But 385 is divisible by 11, also 495, 253, and many others you can try for fun.
If we take the square of x and square of y and then subtract them:
(csc t)²-(cot t)²=1 ( this eq. gets from basic identity
x²-y²=1......a 1+cot²x=csc²x)
equation 'a' represent the equation of hyperbola which is (x²/a²)-(y²/b²) =1 with given conditions( a=1,b=1)
So, option D is correct
It would cost $72 dollars to cover the larger garden
The method used is Distributive Property.
<h3>What is Distributive property?</h3>
The Distributive Property is an algebraic property that is used to multiply a single value and two or more values within a set of parenthesis.
Given:
(2x² - 1)(3x+2) = (2x²)(3x) + (2x²)(2) + (-1)(3x)+(-1)(2)
Here the property used is Distributive property.
Because distributive property in this way
a*(b+c)= a*b+ a*c
This is how a is being multiplied by with b and c.
Learn more about this Distributive property here:
brainly.com/question/4136433
#SPJ1
Answer:
300 Square feet
Step-by-step explanation:
Susan built a rectangular fence around her swimming pool.
Length=15ft
Width(or Breadth)=10ft
Height=6ft
To solve this, picture a cuboid with the top and bottom open, that is the key to finding the Surface Area of the Fence.
Surface Area of a Cuboid= 2(LW+LH+WH)
However since the top and bottom are open, the Surface Area becomes
Surface Area of the fence= 2(LW+WH)
=2((15X6)+(10X6)
=2(90+60)=2 X 150 =300
Susan uses 300 Square feet to build her fence.
