Answer:
The probability that the person is between 65 and 69 inches is 0.5403
Step-by-step explanation:
Mean height = ![\mu = 66](https://tex.z-dn.net/?f=%5Cmu%20%3D%2066)
Standard deviation = ![\sigma = 2.5](https://tex.z-dn.net/?f=%5Csigma%20%3D%202.5)
We are supposed to find What is the probability that the person is between 65 and 69 inches i.e.P(65<x<69)
![Z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
At x = 65
![Z=\frac{65-66}{2.5}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7B65-66%7D%7B2.5%7D)
Z=-0.4
Refer the z table for p value
P(x<65)=0.3446
At x = 69
![Z=\frac{69-66}{2.5}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7B69-66%7D%7B2.5%7D)
Z=1.2
P(x<69)=0.8849
So,P(65<x<69)=P(x<69)-P(x<65)=0.8849-0.3446=0.5403
Hence the probability that the person is between 65 and 69 inches is 0.5403
Answer:
₹ 4000
Step-by-step explanation:
Sarah's salary =₹ 30000
- one-tenth of her salary to an orphanage= 1/10*₹ 30000= ₹ 3000
- one-third of her salary is spent on food= 1/3*₹ 30000= ₹ 10000
- one-fourth of salary on rent and electricity =1/4*₹ 30000= ₹ 7500
- one-twentieth of her salary on the telephone= 1/12*₹ 30000= ₹ 2500
- donated some amount to the Prime Minister's relief fund = x
- She was left with ₹ 3000.
x= ₹ 30000- (₹ 3000+₹ 10000+₹ 7500+₹ 2500+₹ 3000)= ₹ 4000
![\bf \underset{dependent}{\stackrel{\textit{songs I can download}}{S(M)}}~~=~~\underset{independent}{\stackrel{\textit{how much memory I have}}{M}}](https://tex.z-dn.net/?f=%5Cbf%20%5Cunderset%7Bdependent%7D%7B%5Cstackrel%7B%5Ctextit%7Bsongs%20I%20can%20download%7D%7D%7BS%28M%29%7D%7D~~%3D~~%5Cunderset%7Bindependent%7D%7B%5Cstackrel%7B%5Ctextit%7Bhow%20much%20memory%20I%20have%7D%7D%7BM%7D%7D)
the memory is the independent, because that can vary at will, so it's independently varying at will, whilst the amount of songs are limited to how much memory there's in the CD, so the songs are dependent on the memory availability.
Answer:
next three digit is 45 and 7
Step-by-step ex:
hope this helps:)
Using the formula (AB +BC) *BC = (DE +CD) *CD
fill i n what is known:
(17 + 4) *4 = (DE +6) *6
21*4 = (DE +6)*6
84 = (DE+6)*6
84/6 = DE+6
14 = DE +6
DE = 14-6
DE = 8