The concentration of the HI solution is 0.75M.
<h3>How do we calculate the required concentration?</h3>
Required concentration of any solution used in titration will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
M₁ & V₁ are the molarity and volume of CsOH.
M₂ & V₂ are the molarity and volume of HI.
On putting all values from the question, we get
M₂ = (1.9)(9.9) / (25) = 0.75M
Hence required concentration of HI solution is 0.75M.
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Answer:
Because isotopes of the same element only differ by a few neutrons. An example is carbon-12 and carbon-14 isotopes which differ by 2 neutrons in their atomic nuclei.
Explanation:
Isotopes of the same element share the same chemical properties because they bear the same number of electrons (remember electrons are what are involved in chemical reactions). Therefore one can't use chemical methods to separate isotopes.
Separating isotopes require mechanical separation using ultra-high-speed centrifuges with very high-resolution power such that the little mass difference between the isotopes (due to differences in neutron numbers) can be used to separate them.
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Answer:
0.925 atm
Explanation:
By Dalton's Law, the total pressure of a gas mixture is the sum of the partial pressure of its components. The vapor pressure of the water is the pressure that some molecules that evaporated do under the liquid surface. The gas and the liquid are at equilibrium. So, the gas mixture is water vapor and hydrogen gas.
Ptotal = Pwater + PH₂
745 = 42 + PH₂
PH₂ = 703 torr
Transforming to atm:
1 atm ------------------760 torr
x ------------------ 703 torr
By a simple direct three rule
760x = 703
x = 0.925 atm
According to the formula of KE.
KE = 1/2m • v^2.
Both of the variables of mass and energy m determines an object's kinetic energy. Assuming the mass of an object is held constant, the change in velocity, or velocity change will dictate the amount of kinetic energy that a particular object posses.
Answer:
the element he has discovered is called Selenium.
Explanation:
Selenium has an atomic number of 34