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AfilCa [17]
2 years ago
9

Suppose you carry out a titration involving 1.90 molar CsOH and an unknown concentration of HI. To bring the reaction to its end

point, you add 9.9 milliliters of CsOH to 25.0 milliliters of HI.
Now you know that you have a _ solution of HI.
Chemistry
1 answer:
Mariulka [41]2 years ago
3 0

The concentration of the HI solution is 0.75M.

<h3>How do we calculate the required concentration?</h3>

Required concentration of any solution used in titration will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

M₁ & V₁ are the molarity and volume of CsOH.

M₂ & V₂ are the molarity and volume of HI.

On putting all values from the question, we get

M₂ = (1.9)(9.9) / (25) = 0.75M

Hence required concentration of HI solution is 0.75M.

To know more about concentration & volume, visit the below link:
brainly.com/question/24697661

#SPJ1

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Answer:- B- SO_4^-^2

Explanations:- Sharing of electrons takes place between non metals and the bond formed by the sharing of electrons is known as covalent bond. In first choice we only have a zinc metal and so no sharing of electrons  would be possible here.

In third choice we have NaCl. Na is a metal and Cl is a non metal. The property of metals is to transfer its valence electrons to the non metal and the bond formed is known as ionic bond. So, third choice is also not correct.

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The chemical formula for lithium fluoride is lif . a chemist determined by measurements that 0.035 moles of lithium fluoride par
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Answer:
mass = 0.907865 grams

Explanation:
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number of moles can be calculated as follows:
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Substitute in the equation to get the mass as follows:
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Hope this helps :)
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