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AfilCa [17]
2 years ago
9

Suppose you carry out a titration involving 1.90 molar CsOH and an unknown concentration of HI. To bring the reaction to its end

point, you add 9.9 milliliters of CsOH to 25.0 milliliters of HI.
Now you know that you have a _ solution of HI.
Chemistry
1 answer:
Mariulka [41]2 years ago
3 0

The concentration of the HI solution is 0.75M.

<h3>How do we calculate the required concentration?</h3>

Required concentration of any solution used in titration will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

M₁ & V₁ are the molarity and volume of CsOH.

M₂ & V₂ are the molarity and volume of HI.

On putting all values from the question, we get

M₂ = (1.9)(9.9) / (25) = 0.75M

Hence required concentration of HI solution is 0.75M.

To know more about concentration & volume, visit the below link:
brainly.com/question/24697661

#SPJ1

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The correct lewis structure for COH2 contains how many covalent bonds?
VARVARA [1.3K]

Answer:

Four covalent bonds.

Explanation:

Hello,

In this case, given the attached picture in which you can find the Lewis dot structure for metanal (formaldehyde) we can see two C-H bonds and two C-O bonds via a double bond, thus, we can compute the type of each bond given the electronegativities of hydrogen, carbon and oxygen which are 2.1, 2.5 and 3.5 respectively:

C-H=2.5-2.1=0.4\\C-O=3.5-2.5=1.0

Thus, since both electronegativity difference are less 1.7 we infer that all of them are covalent, therefore, it has four covalent bonds, two C-H bonds and a double C-O bond.

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Draw the expanded structural formula for the condensed formula (CH3)2CHCH2OCH2CH3 . Draw all hydrogen atoms
prisoha [69]

We have that the Complete Expanded Structure of (CH3)2CHCH2OCH2CH3 is given in the attachment below

From the Question

(CH3)2CHCH2OCH2CH3

Generally for the condensed formula (CH3)2CHCH2OCH2CH3

We consider that this is a single bond connecting them

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In conclusion

The Complete Expanded Structure of (CH3)2CHCH2OCH2CH3 is given in the attachment below.

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What mass, in grams, of sodium sulfate is needed to make 230.5 g of a 3.5 % (m/m) aqueous solution of sodium sulfate?
andreev551 [17]

The percent concentration of a solution can be calculated from; mass of solute /mass of solution * 100. The mass of the solute here is 8.1 g.

<h3>What is concentration?</h3>

The term concentration refers to the amount of solute presnt in a solution. There are many ways of expressing concentration such as molarity, molality and percentage.

Here;

mass of solution = 230.5 g

Percent of solute =  3.5 %

3.5 = x/ 230.5 * 100

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x = 230.5(3.5) /100

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