The study strategy Lauren is using in spreading her study sessions over a period of time is pacing, which helps the student develop a schedule focused on their own study pace.
<h3>Pacing Study Sessions</h3>
This study strategy of distributing the study into short sessions rather than studying the entire content through one long session is more effective in retaining content and learning.
What happens is that Lauren is using mass repetition processing, which can be compared to a longitudinal wave in physics, with spaces in between, concentrating the initial review close to the proof to ensure retention and avoid forgetting.
Through pacing, Lauren achieves greater motivation to carry out her studies in a concentrated and focused way, helping her to retain and preserve knowledge.
The correct answer is:
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Answer:
Water gradually degrades them until the metal parts rust and the other materials deteriorate.
Explanation:
Answer: There are
atoms in 24 moles of Fe.
Explanation:
According to the mole concept, 1 mole of a substance contains
atoms.
Therefore, atoms present in 24 moles of Fe are calculated as follows.

Thus, we can conclude that there are
atoms in 24 moles of Fe.
Answer:
A, T, C y G, son las "letras" del código del ADN; representan los compuestos químicos adenina (A), timina (T), citosina (C) y guanina (G), respectivamente, que constituyen las bases de nucleótidos del ADN. ...El código genético es el conjunto de reglas que define cómo se traduce una secuencia de nucleótidos en el ARNm a una secuencia de aminoácidos en una proteína
According to ideal gas equation, we know for 1 mole of gas: PV=RT
where P = pressure, T = temperature, R = gas constant, V= volume
If '1' and '2' indicates initial and final experimental conditions, we have

Given that: V1 = 100.0 kPa, T1 = 100.0 K, V1 = 2.0 m3, T2 = 400 K, P2 = 200.0 kPa
∴ on rearranging above eq., we get V2 =

∴ V2 = 4 m3