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salantis [7]
3 years ago
10

What factors determine an objects kinetic energy

Chemistry
2 answers:
gladu [14]3 years ago
8 0

Answer:

its mass and speed

Explanation:

ludmilkaskok [199]3 years ago
6 0
According to the formula of KE.

KE = 1/2m • v^2.

Both of the variables of mass and energy m determines an object's kinetic energy. Assuming the mass of an object is held constant, the change in velocity, or velocity change will dictate the amount of kinetic energy that a particular object posses.
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If an object has a density of 0.55 g/mL, what is its density in cg/L?
otez555 [7]

if              1 g is equal to 100 cg

then  0.55 g are equal to X cg

X = (0.55 × 100 ) / 1 = 55 cg

The density of the object is 55 cg/L.

7 0
3 years ago
Read 2 more answers
AICI3(s)+Ca 3N2(s)-AIN(S)+CaCl2(s)
disa [49]

Answer:

2AlCl3 + Ca3N2 - 2AlN+ 3CaCl2

8 0
2 years ago
How many moles of hydrogen are required to react with 4.6 x 10 22 molecules of nitrogen?
V125BC [204]

Answer: 6 moles

Take a look at the balanced chemical equation for this synthesis reaction

N 2(g] + 3 H 2(g] → 2 NH 3(g]

Notice that you have a  1:3  mole ratio between nitrogen gas and hydrogen gas. This means that, regardless of how many moles of nitrogen gas you have, the reaction will always consume twice as many moles of hydrogen gas.

So, if you have  2 moles of nitrogen taking part in the reaction, you will need

2 moles N 2 ⋅ 3 moles H 2 /1 mole N 2 = 6 moles H 2

8 0
3 years ago
The question is "How does the absorption and release of energy affect temperature change during a chemical reaction?" I need to
sergeinik [125]
If the heat is absorbed, then the temperature will increase as well.
3 0
3 years ago
The Hall process for the production of aluminum involves the reaction of aluminum oxide with elemental carbon to give aluminum m
topjm [15]

Answer:

  • <u><em>1.7 × 10³ kg of ore.</em></u>

Explanation:

Call X the amount of aluminum ore mined to produce 1.0 × 10³ kg the aluminum metal.

Then, taking into account the yield of the reaction (82 % = 0.82) and the percent of aluminun in the ore (71% = 0.71), you can write the following equation:

  •  X         ×          71%                ×       82%     =     1.0 × 10³ kg

         ↑                      ↑                              ↑                     ↑

(mass of ore)    (% of Al in the ore)        (yield)        ( Al metal to obtain)

You must just simplify, solve and compute:

  • 0.71 × 0.82 × X = 1,000
  • X = 1,000 / (0.71 × 0.82) = 1,000 / 0.5822 = 1,717.6 Kg

Round to two significant figures; 1,700 kg = 1.7 × 10³ kg of ore ← answer.

6 0
3 years ago
Read 2 more answers
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