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Angelina_Jolie [31]
3 years ago
6

A 55.0-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300. What h

orizontal force must be applied to the box for it to start sliding along the surface?
Physics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

161.86 N

Explanation:

mass of box m= 55.0 kg

weight of the box, mg= 55×9.81

g here is acceleration due to gravity =9.81 m/sec^2

coefficient of friction between the box and the surface μ= 0.3

the friction force F_s= μmg= 0.3×55×9.81

=161.86 N

to move the ball horizontal force required is 161.86 N

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A 3kg box has 45J of gravitational potential energy, how high is it off the ground?
frez [133]

Answer:

1.53m

Explanation:

Given parameters:

Mass of box  = 3kg

Gravitational potential energy  = 45J

Unknown

Height of the box  = ?

Solution:

To solve this problem;

 Gravitational potential energy = mgh

m is the mass

g is the acceleration due to gravity

h is the height

            45  = 3 x 9.8 x h

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Answer:

Option A applies.

A.  Greater than its escape speed from the mass within the volume

Explanation:

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3 0
3 years ago
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weqwewe [10]

Answer:The correct options are:

1. A system is a group of objects analyzed as one unit.

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Explanation:

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Two statements are true about a system:

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3 0
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alexdok [17]
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6 0
3 years ago
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mash [69]

Answer:

-3+3 i think this is the answer

Explanation:

i think you can ask someone else sorry

4 0
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