is the equation that represents the Joule's law of heating.
<h3>
Explanation:</h3>
Joule's law of heating defines the heat generated by any current flowing conductor is directly proportional to
1. Square of Current (I²),
2. Resistance of the conductor (R)
3. Time for which current is passed (t)
Hence, Heat generated = 
.....................(1)
By Ohm's Law, the potential difference (V) across a conductor is directly proportional to the current(I) flowing through it. The constant of proportionality is termed as resistance of the conductor (R).
...............................................(2)
From (2), Current (I) can be rewritten as
........................................................(3)
Substituting (3) in (1), we get
Answer: 
Explanation:
The <u>centripetal acceleration</u> 
of an object moving in a uniform circular path is given by the following equation:
(1)
Where:
is the tangential velocity
is the radius of the circle
On the other hand, the tangential velocity is expressed as:
(2)
Where 
is the angular velocity, which can be found knowing the child makes 5 revolutions in 13.4s:
(3)
Substituting (3) in (2):
(4)
(5)
Substituting (5) in (1):
(6)
Finally:
Mercury,Venus,Earth and Mars
<span>A full moon is at its brightest, and here is no disk to be seen. New moons are barely visable.</span>
Answer:
Both balls will hit the ground at the same time
Explanation:
The factor which leads to ball falling is the gravity acting on the ball;
The motions along the path of both balls are independent and both balls will obey the following illustration
Using the third equation of motion
s = ut + ½at²
Where s = distance covered by both balls.
u = initial velocity of both balls. Since both balls start from rest, u = 0m/s
a = acceleration; and it's equal to acceleration due to gravity.
a = g
By substituton
s = 0 * t + ½gt²
s = 0 + ½gt²
s = ½gt²
Make t the subject of formula
gt² = 2s
t² = 2s/g
t = ±√(2s/g)
But time can't be less than 0 (in other words, negative)
So,
t = √(2s/g)
It'll take both balls √(2s/g) time to hit the floor
