Similar elements with similar properties were in the same groups and periods for instance lithium(Li) and sodium(Na) are alkaline metals and so belong to the same group (that is group 1).Also Hydrogen(H) and Helium(He) both have only one shell or energy level and so belong to the same period.
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K (Q1) (Q2)/d^2 =
k : coulumb constant
Q1 : Charge on object 1
Q2 : Charge on object 2
d : distance between two charged object
Explanation:
Given that,
Radius R= 2.00
Charge = 6.88 μC
Inner radius = 4.00 cm
Outer radius = 5.00 cm
Charge = -2.96 μC
We need to calculate the electric field
Using formula of electric field
![E=\dfrac{kq}{r^2}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7Bkq%7D%7Br%5E2%7D)
(a). For, r = 1.00 cm
Here, r<R
So, E = 0
The electric field does not exist inside the sphere.
(b). For, r = 3.00 cm
Here, r >R
The electric field is
![E=\dfrac{kq}{r^2}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7Bkq%7D%7Br%5E2%7D)
Put the value into the formula
![E=\dfrac{9\times10^{9}\times6.88\times10^{-6}}{(3.00\times10^{-2})^2}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B9%5Ctimes10%5E%7B9%7D%5Ctimes6.88%5Ctimes10%5E%7B-6%7D%7D%7B%283.00%5Ctimes10%5E%7B-2%7D%29%5E2%7D)
![E=6.88\times10^{7}\ N/C](https://tex.z-dn.net/?f=E%3D6.88%5Ctimes10%5E%7B7%7D%5C%20N%2FC)
The electric field outside the solid conducting sphere and the direction is towards sphere.
(c). For, r = 4.50 cm
Here, r lies between R₁ and R₂.
So, E = 0
The electric field does not exist inside the conducting material
(d). For, r = 7.00 cm
The electric field is
![E=\dfrac{kq}{r^2}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7Bkq%7D%7Br%5E2%7D)
Put the value into the formula
![E=\dfrac{9\times10^{9}\times(-2.96\times10^{-6})}{(7.00\times10^{-2})^2}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B9%5Ctimes10%5E%7B9%7D%5Ctimes%28-2.96%5Ctimes10%5E%7B-6%7D%29%7D%7B%287.00%5Ctimes10%5E%7B-2%7D%29%5E2%7D)
![E=5.43\times10^{6}\ N/C](https://tex.z-dn.net/?f=E%3D5.43%5Ctimes10%5E%7B6%7D%5C%20N%2FC)
The electric field outside the solid conducting sphere and direction is away of solid sphere.
Hence, This is the required solution.