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Marianna [84]
3 years ago
9

Find the distance between the points given. (0.5) and (-5, 0)

Mathematics
1 answer:
Andrew [12]3 years ago
8 0

Answer:

I cant help unless i have workable units (0.5) is not a point

but im guessing that you were trying to say (0,5) in which case its

7.07106781187

its a triangle

5 on one side

5 on the other

solve for the hypotenuse

hypotenuse = \sqrt{50}

hypotenuse = 7.07106781187

I hope this helps!

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7nadin3 [17]
<h3>Answer: Choice (d)</h3>

Explanation:

To reflect over the y axis, we apply this rule

(x,y) \to (-x,y)

which says to flip the sign of the x term but keep the y coordinate the same.

So that means something like J(-2,5) becomes J ' (2, 5). The other points are handled in the same fashion and that leads us to choice (d). Points on the y axis will stay where they are.

6 0
3 years ago
AM MARKING BRAINIEST!!!
xxMikexx [17]

Answer:

1.25

Step-by-step explanation:

3.75 divided by 3 = 1.25

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Read 2 more answers
Match each series with the equivalent series written in sigma notation
PIT_PIT [208]

Answer:

3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n

2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

3 + 12 + 48 + 192 + 768

The expression can be written as:

3 \to 3*4^{0 --- 0

12 \to 3 * 4^{1 ---- 1

48 \to 3 * 4^{2 --- 2

192 \to 3 * 4^{3 ---- 3

768 \to 3 * 4^{4 ---- 4

For the nth term, the expression is:

Term = 3 * 4^{n ---- n

So, the summation is:

3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

Solving (b):

4 + 32 + 256 + 2048 + 16384

The expression can be written as:

4 \to 4 * 8^0 --- 0

32 \to 4 * 8^1 ---- 1

256 \to 4 * 8^2 --- 2

2048 \to 4 * 8^3 ---- 3

16384 \to 4 * 8^4 ---- 4

For the nth term, the expression is:

Term \to 4 * 8^n ---- n

So, the summation is:

4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n

Solving (c):

2 + 6 + 18 + 54 + 162

The expression can be written as:

2 \to 2 * 3^0 --- 0

6 \to 2 * 3^1 ---- 1

18 \to 2 * 3^2 --- 2

54 \to 2 * 3^3 ---- 3

162 \to 2 * 3^4 ---- 4

For the nth term, the expression is:

Term \to 2 * 3^n ---- n

So, the summation is:

2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n

Solving (d):

3 + 15 + 75 + 375 + 1875

The expression can be written as:

3 \to 3 * 5^0 --- 0

15 \to 3 * 5^1 ---- 1

75 \to 3 * 5^2 --- 2

375 \to 3 * 5^3 ---- 3

1875 \to 3 * 5^4 ---- 4

For the nth term, the expression is:

Term \to 3 * 5^n ---- n

So, the summation is:

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

5 0
3 years ago
Find the missing measurement. Use 3.14 for it.*
Anarel [89]

Answer:

452.16 mm squared is a correct answer.

Sure!

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3 0
3 years ago
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8_murik_8 [283]

Answer:

A.9

F.27

Step-by-step explanation:

how i got 9 is by counting by 9 and i count 27,and 54

additional 27 times 2= 54

5 0
4 years ago
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