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disa [49]
3 years ago
11

Can anyone help me answer this ?

Mathematics
1 answer:
AfilCa [17]3 years ago
7 0

It would be y=7/2x+5/7

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The probability of randomly selecting a name starting with the letter T from a bowl of 24 names is . Which of the following desc
lara31 [8.8K]
The probability of randomly selecting a name starting with the letter T from bowl of 24 names depends on the names that are in the bowl,. The number 24 says nothing about the names. There can be neither probability that the randomly selected name starts with T, if in the bowl none of the 24 names starts with T. 
It could be also unlikely to select a name starting with T if there is a really small number of names in the bowl starting with T (for example 1 or 2 from 24). And it can be likely to chose a name  that start with T if there are many names in the bowl starting with T.So, it is important to know the number of names in the bowl starting with T. 
3 0
3 years ago
What is The difference between 3 7/10 and 2 2/5
miskamm [114]

Answer:

1 3/10

Step-by-step explanation:

3 7/10 - 2 2/5 =

3 7/10 - 2 4/10 =

1 3/10

7 0
3 years ago
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2/2 - 7x-4<br> Simplify<br> - 58+4<br> 2x + 1<br> 2-1<br> 2x + 1<br> *+1<br> 2-72
Pachacha [2.7K]

Answer:

A or (2x+1)/(x-1)

Step-by-step explanation:

Let's simplify the top of the fraction first.

1. Simplify the numerator.

2x^2 -7x-4=(2x+1)(x-4)

2. Simplify the denominator.

x^2-5x+4=(x-4)(x-1)

Now we have:

((2x+1)(x-4))/((x-4)(x-1))

We see that there is an (x-4) both on the numerator and denominator.

We can remove (x-4) by division.

Doing that, we have:

(2x+1)/(x-1) or A

5 0
3 years ago
Please help!!! I’ll mark you as brainliest!!!!!
kherson [118]
<h2>Answer:</h2><h2>80%.</h2>

Step-by-step explanation:

8 0
3 years ago
Write a quadratic equation that can be solved by factoring. Solve your equation and show and explain all your work.
miv72 [106K]

Answer:

An example of a quadratic equation is:

{x}^{2}  + 5x + 6 = 0

Step-by-step explanation:

This answer follows the standard form for a quadratic equation:

a {x}^{2}  + bx + c = 0

To solve this equation you do the following:

x^2 + 5x + 6 =0

The factors that can be added to get *5* and multiplied to get *6* are 3 & 2.

Therefore the new equation would be:

x^2 +3x + 2x + 6 = 0

<em>group the terms</em>: (x^2 +3x) (+2x + 6) = 0

<em>factorize</em><em>:</em><em> </em>x (x + 3) 2 (x + 3) = 0

<em>therefore</em><em>:</em><em> </em><em>(</em><em>x</em><em> </em><em>+</em><em> </em><em>2</em><em>)</em><em> </em><em>(</em><em>x</em><em> </em><em>+</em><em> </em><em>3</em><em>)</em><em> </em><em>=</em><em>0</em>

<em>x</em><em> </em><em>=</em><em> </em><em>-1</em><em> </em><em> </em><em>x</em><em> </em><em>=</em><em>-3</em>

4 0
2 years ago
Read 2 more answers
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