Question

The sum of three consecutive integers is 63. What is the lowest of the three integers?

Answer 1

  One number be x
x+(x+1)+(x+2)=63
x+x+1+x+2=63
3x+3=63
3x=63-3
3x=60
x=60:3
x=20
smallest number = x=20
middle number = x+1= 20+1=21
largest number = x+2 =20+2= 22