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Leno4ka [110]
3 years ago
10

How many more students studied for at least 3 hours compared to students who studied

Mathematics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

5 students

Step-by-step explanation:

9 students studied for more than 3 and 4 students studied less .

9-4=5

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When Victoria goes bowling, her scores are normally distributed with a mean of 130
Artemon [7]

Answer:

0.2377 or about a 23.77% chance

Step-by-step explanation:

P(123<X<130) = normalcdf(123,130,130,11) = 0.2377303466 ≈ 0.2377

Therefore, the probability that the next game Victoria bowls, her score will be  between 123 and 130 is 0.2377 or about a 23.77% chance

5 0
3 years ago
N+4-9 - 5n when simplifying
natita [175]

Answer:

-4n - 5

Step-by-step explanation:

4 - 9

= -5

-5n + n

Combine like terms

= -4n

-4n - 5

7 0
3 years ago
Jessa started with 100 sugar cookies for the Christmas banquet and gave away x cookies. Cooper started with 120 cookies but gave
masya89 [10]

Answer:

20 cookies

Step-by-step explanation:

To find the answer start by plugging in numbers. first, subtract the number from 100 or Jessa's number of cookies then multiply that by 2 and subtract that from 120 or Cooper's cookies. If the two resulting numbers are equal then you have the right answer.

5 0
2 years ago
8.7 × 10 to the 5th power in standard form
Andrej [43]
Answer would be 870000
6 0
3 years ago
Read 2 more answers
Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*
dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\

5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\

\mathrm{Solve\:}\:k-5=0:\quad k=5\\\\k =5 , k=-3

7 0
3 years ago
Read 2 more answers
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