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Neko [114]
2 years ago
7

What is the value of | 7 |?​

Mathematics
2 answers:
Andrew [12]2 years ago
5 0

Answer:

7 the brackets just makes any number in there positive

Step-by-step explanation:

9966 [12]2 years ago
3 0

Answer: for pozitive numbers its just the number in this case 7

Step-by-step explanation: if it was | -7 | it wood be 7

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What ratio is equivalent to 1/7
Rzqust [24]
14/2 is equivalent to 7/1
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2 years ago
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Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
The area of a rectangular field is 5695 m².
denpristay [2]

Answer:

85 m

Step-by-step explanation:

5696/67=85

3 0
2 years ago
One circular table has a diameter of 8 ft, and another circular table has a diameter of 12 ft. How much greater is the area of t
mezya [45]

Answer:

20π sq ft ≈ 62.83 sq ft

Step-by-step explanation:

Area of table with diameter 8 ft = π*8^2/4 = 16π

Area of table with diameter 12 ft = π*12^2/4 = 36π

Difference between the area of the tables ;

= 36π - 16π

= 20π sq ft ≈ 62.83 sq ft                              ( π = 3.14)

8 0
3 years ago
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How many solutions does the polynomial equation ( x+8)2( x-1) = 0
Olin [163]

Answer:

-8 and 1

Step-by-step explanation:

8 0
3 years ago
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