Theorem of cosine:
a²=b²+c²-2bc(cos α) ⇒cos α=-(a²-b²-c²) / 2bc
In this case:
a=15 cm
b=10 cm
c=5 cm
cos α=-(15²-10²-5²) / 2*10*5
cos α=-100 / 100
cos α=-1
A=arc cos -1=180º This is impossible, because:
A+B+C=180º; then B=C=0º This is impossible for make a triangle (B>0 and C>0 if we want to make a triangle).
Therefore: it is not possible can make a triangle with side lengths of 5 cm, 10 cm and 15 cm.
Answer:
D) y = 27 · (3)^x
Step-by-step explanation:
Replace x with the x values.
27 · (3)^-2 = 27 · 1/9 = 3
27 · (3)^-1 = 27 · 1/3 = 9
27 · (3)^0 = 27 · 1 = 27
27 · (3)^1 = 27 · 3 = 81
17 · (3)^2 = 27 · 9 = 243
D is your answer.
Hope this helps
Answer:
3/4
Step-by-step explanation:
Use the rise over run equation
Answer:
x = 5/(10 - a - b)
Step-by-step explanation:
Solve for x:
4 + 3 x - a x = 9 - 7 x + b x
Collect in terms of x:
x (3 - a) + 4 = 9 - 7 x + b x
Collect in terms of x:
x (3 - a) + 4 = x (b - 7) + 9
Subtract (b - 7) x + 4 from both sides:
x (10 - a - b) = 5
Divide both sides by 10 - a - b:
Answer: x = 5/(10 - a - b)
