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Svetlanka [38]
3 years ago
9

If you don’t know the answer or full explanation, then please don’t answer at all. Thank you for helping!

Mathematics
1 answer:
KatRina [158]3 years ago
5 0

Answer:

<em>The domain of the function is (-6,6]</em>

<em>The range of the function is [-12.6)</em>

Step-by-step explanation:

<u>Domain and Range of Real Functions</u>

The domain of a function is the set of all possible inputs for the function.

The Range is the set of values the function takes when x moves into the domain.

If the graph of a real function is given, we can find both by using the rules of the horizontal or vertical lines.

If an imaginary vertical line is moved along the x-axis, it can touch or not the graph of the function. All the values of x where the line and the graph cross each other belong to the domain of the function.

The vertical line crosses the function from x=-6 (not included since there is a hollow dot there) to x=6 (included since there is a solid dot).

Thus, the domain of the function is (-6,6]

Similarly, when an imaginary horizontal line is moved along the y-axis, it touches the function from y=-12 (included) to y=6 (not included).

The range of the function is [-12.6)

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24. Which measurement is equivalent to 10 g?<br> a. 1 dag<br> b. 1 dg<br> c. 1 cg<br> d. 1 hg
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Step-by-step explanation:

The list of SI prefixes is attached. Each has an abbreviation that can be used with the abbreviation for the SI unit of interest.

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2 years ago
If , find the value of 2 square root of 17-x = 2x-10, find the value of x/4.
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2 \sqrt{17-x} =2x-10\ \ \ \ \Rightarrow\ \ \ D:(17-x \geq 0\ \ \ and\ \ \ 2x-10 \geq 0)\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \leq 17\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ x \geq 5\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=\\\\2 \sqrt{17-x} =2(x-5)\ /:2\\\\ \sqrt{17-x} =x-5\ \ \ \Rightarrow\ \ \ (\sqrt{17-x})^2 =(x-5)^2\\\\17-x=x^2-10x+25\\\\

x^2-9x+18=0\\\\ x^2-3x-6x+18=0\\\\x(x-3)-6(x-3)=0\\\\(x-3)(x-6)=0\ \ \ \ \Leftrightarrow\ \ \ (x-3=0\ \ \ \ or\ \ \ \ x-6=0)\\\\x=3\ \notin\ D\ \ \ \ \ \ \ \ \ \ \ x=6\ \in\ D\ \ \ \Rightarrow\ \ \  \frac{x}{4} = \frac{6}{4} =1.5\\\\Ans.\  \frac{x}{4} =1.5
7 0
3 years ago
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