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3 years ago

9

-2 with a exponent six

2 answers:

kykrilka [37]3 years ago

8 0

An exponent is how many times a number is multiplied by itself. So in this case that would be -2 x-2 x-2 x-2 x-2 x-2. -2 x-2=4. 4x-2=-8. -8x-2=16. 16x-2=-32. -32x-2=64. Hope this helps :)

DIA [1.3K]3 years ago

5 0

$-2^{6} 

$ = -2 with a exponent six
Well Exponents mean that you multiply the number 6 times.
Soo..
$-2^{6}$ = -2 x -2 x -2 x -2 x -2 x -2 = 64

So <span> $-2^{6}$ = 64
</span>
Good Luck! :)

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Determine whether each ordered pair is a solution of the system.

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8 0

3 years ago

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Answer:

$F = 1.8C +32$

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8 0

3 years ago

Read 2 more answers

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xxMikexx [17]

Answer:

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Step-by-step explanation:

We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

Now, we have, $\frac{1}{x-6} +\frac{x}{x-2} = \frac{4}{x^{2}-8x+12 }$

⇒ $\frac{(x-2)+x(x-6)}{(x-2)(x-6)} = \frac{4}{x^{2}-8x+12 }$

⇒ $\frac{x-2+x^{2}-6x }{(x-2)(x-6)} =\frac{4}{(x-2)(x-6)}$

⇒ $\frac{(x-2)(x-6)}{x^{2}-5x-2 }=\frac{(x-2)(x-6)}{4}$

⇒ $(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$

⇒ $(x-2)(x-6) =0$ or, $[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$

If, (x-2)(x-6) =0, then x=2 or x=6

If, $[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$ , then $x^{2} -5x-2=4$

and (x-6)(x+1) =0

Therefore, x=6 or -1

So the solutions for x are -1, 2 6. (Answer)

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3 years ago