For this case we have the following system of equations:
Equating both equations we have:
We must find the solutions, for this we factor. We look for two numbers that, when multiplied, result in 4 and when added, result in 5. These numbers are 4 and 1:
Then, the factorized equation is of the form:
Thus, the solutions are:
We look for solutions for the variable "y":
Thus, the system solutions are given by:
ANswer:
I feel like there is something missing from this question, for example how large is the tree house? If these are just plain measurements, then I would opt for B.
Both trees would be the same in 2 years at 7 feet.
Hope this helps.
U+(v-t)
that’s the answer!
1-2. The best estimate for the population mean would be sample mean of 60 gallons. Since we know that the sample mean is the best point of estimate. Since sample size n=16 is less than 25, we use the t distribution. Assume population from normal distribution.
3. Given a=0.1, the t (0.05, df = n – 1 = 15)=1.75
4. xbar ± t*s/vn = 60 ± 1.75*20/4 = ( 51.25, 68.75)
5. Since the interval include 63, it is reasonable.
