Hey there! :D
Find the unit rate.
275/2= 137.5
Cade shoots 137.5 free throws per hour. Multiply that by 5 for 5 hours.
5*137.5= 687.5
He can shoot 687.5 free throws in one hour. You could just round that to 688.
I hope this helps!
~kaikers
9514 1404 393
Answer:
12 minutes
Step-by-step explanation:
Let c and h represent the filling times for the cold and hot taps, respectively. When the cold tap is 1/2 open, we presume that means the filling time becomes 2c.
In terms of baths per minute, the relationships are ...
1/c + 1/h = 1/3
1/(2c) +1/h = 1/(3 +1.8) . . . . . 1:48 min:sec is 1.8 minutes
Subtracting the first equation from twice the second, we get ...
2(1/(2c) +1/h) -(1/c +1/h) = 2(1/4.8) -(1/3)
1/h = 2/4.8 -1/3 = 1/12
h = 12
It takes the hot tap 12 minutes to fill the tub alone.
It’s should be something like negative 7or 8
2 is distribution blah blah
Answer:
Step-by-step explanation:
Given (64 y Superscript 100 Baseline) Superscript one-half.
Let us write it into an equation.
Apply radical rule: ![\sqrt[n]{a}=a^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
and 
![\begin{aligned}\left(64 y^{100}\right)^{\frac{1}{2}} &=\sqrt[2]{64 y^{100}} \\&=\sqrt[2]{8^{2} y^{50} y^{50}} \\&=\sqrt[2]{8^{2}\left(y^{50}\right)^{2}} \\&=8 y^{50}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cleft%2864%20y%5E%7B100%7D%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%26%3D%5Csqrt%5B2%5D%7B64%20y%5E%7B100%7D%7D%20%5C%5C%26%3D%5Csqrt%5B2%5D%7B8%5E%7B2%7D%20y%5E%7B50%7D%20y%5E%7B50%7D%7D%20%5C%5C%26%3D%5Csqrt%5B2%5D%7B8%5E%7B2%7D%5Cleft%28y%5E%7B50%7D%5Cright%29%5E%7B2%7D%7D%20%5C%5C%26%3D8%20y%5E%7B50%7D%5Cend%7Baligned%7D)
Hence, is equivalent to (64 y Superscript 100 Baseline) Superscript one-half.
