Answer:
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Answer: The measure of AC is 32.
Explanation:
It is given that the Points B, D, and F are midpoints of the sides of ΔACE. EC = 38 and DF = 16.
The midpoint theorem states that the if a line segments connecting two midpoints then the line is parallel to the third side and it's length is half of the third side.
Since F and D are midpoints of AE and EC respectively.
So by midpoint theorem length of AC is twice of DF.



Therefore, the length of AC is 32.
Answer:it goes up by 2 so it would be 3+2 is 5 5+2=7 and so on
Step-by-step explanation:
Answer:
Reflect and compress
Step-by-step explanation:
Answer:
⅘ or 0.8
Step-by-step explanation:
Hypotenuse² = 3² + 4²
Hypotenuse = 5
Sin(θ) = 4/5