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Novay_Z [31]
3 years ago
5

12. (2v^3 - v + 8) + (-v^3 + v - 3) 14. (4h^3 + 3h + 1) - (-5h^3 + 6h - 2)

Mathematics
1 answer:
Lana71 [14]3 years ago
7 0
12. On addition, you can just combine like terms.
2v^3+(-v^3)=v^3
-v+v cancels each other out
8+(-3)=5
So you have v^3+5

14 On subtraction, you have to remember to distribute the negative sign so after you do that you have:
4h^3+3h+1+5h^3-6h+2
Then you can combine like terms
4h^3+5h^3=9h^3
3h-6h=-3h
1+2=3
So you end up with:
9h^3-3h+3

Hope that helps and feel free to ask any questions.
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A car requires 22 litres of petrol to travel a distance of 259.6 km.Find
Anon25 [30]

Answer:

Step-by-step explanation:

1. A car requires 22 litres of petrol to travel a distance of 259.6 km

what is the distance that the car can travel on 63 ltr of petrol

22ltr = 259.6km

63ltr=

cross multiply

{63 x 259.6}/22 = 16354.8/22 = 743.4 km

A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km

2. To travel a distance of 2013.2 km

we would need to calculate the amount of fuel

A car requires 22 litres of petrol to travel a distance of 259.6 km

what amount of fuel would it require to travel 2013.2km

22ltr = 259.6km

xltr = 2013.2km

x is the value of petrol to cover 2013.2km

cross multiply

(2013.2 x 22)/259.6

44290.4/259.6 = 170.610169492≈170.6 ltr

A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km

if 1ltr is $1.99

170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5

The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5

5 0
3 years ago
Problemas de razonamiento división de números decimales. Ayer Susana se fue de viaje a visitar a unos familiares. Recorrió 135,7
schepotkina [342]

Usando las relaciones entre velocidad, distancia y tiempo, se encuentra que ella condujo a una velocidad media de 90,5 km/h.

--------------------------

La <u>velocidad </u><u>es la distancia dividida por el tiempo</u>, por lo que:

v = \frac{d}{t}

  • Total de 135,75 km, o sea, d = 135,75
  • Llego en 1,5 horas, o sea, t = 1,5

La velocidad es:

v = \frac{d}{t} = \frac{135,75}{1,5}

División de decimales, o sea, seguimos multiplicando los números por 10 hasta que ninguno sea decimal:

v = \frac{135,75}{1,5} = \frac{1357,5}{15} = \frac{13575}{150} = 90,5

Ella condujo a una velocidad media de 90,5 km/h.

Un problema similar es dado en brainly.com/question/24558377

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