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3 years ago

SIS HELP!! How many pennies are on the nth square?

Mathematics

2 answers:

anyanavicka [17]3 years ago

4 0

Answer:

B. , just did the assignment

ivann1987 [24]3 years ago

4 0

Answer:

The answer is B, 2^n - 1

Step-by-step explanation:

took the assignment on edge 2020

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Help, please!! What is mA?

Inga [223]

Answer:

38°

Step-by-step explanation:

The measure of required angle can be obtained by using cosine law.

From the given triangle we find that:

a = 5, b = 3, c = 7,

Since,

cos (A) = (b^2 +c^2 - a^2) /2bc

Therefore,

cos (A) = (3^2 + 7^2 - 5^2) /(2*3*7)

cos (A) = (9 + 49 - 25) /(42)

cos (A) = (33) /(42)

cos (A) = 0.785714286

A = arccos(0.785714286)

A = 38.213210675°

A = 38°

4 0

3 years ago

Divide. (2x²+17x+28)÷(x+6)

oksian1 [2.3K]

Answer:

2x2+17x+28/x+6

Step-by-step explanation:

6 0

3 years ago

What is the perimeter of the figure? A. 144 cm B. 76 cm C. 74 cm D. 45 cm

tatiyna

76 cm would be your answer, so B.

8 0

3 years ago

Read 2 more answers

Two angles of a triangle measure 45 degrees and 90 degrees. What is the third angle measure?

neonofarm [45]

Answer:

Step-by-step explanation:

Angles in a triangle add up to 180

Take 45 + 90 then subtract the answer from 180

6 0

2 years ago

A rug is to be centered in a room so that the border around it is of a consistent width on all four sides. If the room is 10 ft

aleksley [76]

Answer:

The width of the border can be 9 feet or 3.5 feet.

Step-by-step explanation:

Let the width be x

Length of room = 10 feet

Breadth of room = 15 feet

Length of rug = 10-2x

Breadth of rug = 15-2x

Area of rug = $(10-2x)(15-2x)$

We are given that the area of the rug is 24 square feet.

So, $(10-2x)(15-2x)=24$ ---A

$150-20x-30x+4x^2=24$

$150-24-50x+4x^2=0$

$126-50x+4x^2=0$

$2(x-9)(2x-7)=0$

$x=9,\frac{7}{2}$

$x=9,3.5$

Substitute x =9 in A

$(10-2(9))(15-2(9))=24$

$24=24$

LHS = RHS

Substitute x = 3.5

$(10-2(3.5))(15-2(3.5))=24$

$24=24$

LHS = RHS

So, The width of the border can be 9 feet or 3.5 feet.

7 0

3 years ago