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lisabon 2012 [21]
3 years ago
12

Hey can anybody give me a teachers answer key on dis lessons

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
3 0
Hm maybe look up the name of the document and put pdf answers
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Graph each linear equation that passes through the given pair of points. Use graph paper.
Naya [18.7K]

Answer:

The easier way to solve this is to find the two points in the coordinate axis, and just draw a line that passes through the two points.

But let's be more complete:

Let's find the equations for each line:

A linear relationship can be written as:

y = a*x + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

1) Here the points are (2,2) and (4,5)

then the slope is:

a = (5 - 2)/(4 - 2) = 3/2

y = (3/2)*x + b

And to find the value of b, we just replace the values of one of the points in the equation, in this case i will use (2, 2)

2 = (3/2)*2 + b

2 = 3 + b

2 - 3 = b

-1 = b

y = (3/2)*x - 1

2) Here the points are (0,1/2) and (2,3/2)

then the slope is:

a = (3/2 - 1/2)/(2 - 0) = 1/2

y = (1/2)*x + b

And to find the value of b, we just replace the values of one of the points in the equation, in this case i will use (0, 1/2)

1/2 = (1/2)*0 + b

1/2 = b

y = (1/2)*x + 1/2

3) Here the points are (-1,2) and (5,0)

then the slope is:

a = (0 - 2)/(5 + 1) = -1/3

y = (-1/3)*x + b

And to find the value of b, we just replace the values of one of the points in the equation, in this case i will use (-1, 2)

2 = (-1/3)*-1 + b

2 = 1/3 + b

2 - 1/3 = b

5/3 = b

y = (-1/3)*x + 5/3

4) Here the points are (-5,-3) and (-3,5)

then the slope is:

a = (5 + 3)/(-3 + 5) = -4

y = -4*x + b

And to find the value of b, we just replace the values of one of the points in the equation, in this case i will use (-3, 5)

5 = -4*-3 + b

5 = 12 + b

5 - 12 = b

-7 = b

y = -4*x - 7

Now that we have all the equations, we can find the graphs.

where the colors are:

(4) green

(3) orange

(2) Blue

(1) Gray.

6 0
3 years ago
Find the distance of a(1,8) and point c (-8,-6) then find the midpoint of ac
mr Goodwill [35]
\text{MIdpoint =} \bigg(\dfrac{1 + (-8)}{2}, \dfrac{8+(-6)}{2} \bigg) = \bigg(\dfrac{-7}{2}\ , \ \dfrac{2}{2} \bigg) = \bigg(-3.5 \ , \ 1 \bigg)

Answer: The midpoint (-3.5, 1)
5 0
3 years ago
PLZZZ HELP ME I WILL GIVE BRAINLY
Goryan [66]

Answer: x is for bouquets and y is for centerpieces.

Step-by-step explanation:

13x+4y=487

6x+2y=232

4 0
2 years ago
Read 2 more answers
Show all your work to find the axis of symmetry of f(x) = −2(x − 4)^2 + 2.
Naya [18.7K]

Answer:

-2(x^2+15)

Step-by-step explanation:

f(x) = −2(x − 4)^2 + 2.

Expanding (x-4)^2

(x-4)(x+4)

x(x+4)-4(x+4)

x^2+4x-4x-16

x^2-16

F(x) = -2(x^2-16)+2

-2x^2-32+2

-2x^2-30

-2(x^2+15)

6 0
3 years ago
55. (a) If alpha and beta are the roots of the equation xsquare+ px+q=0 and beta>alpha find the square of the
densk [106]

Answer:

√(p²-4q)

Step-by-step explanation:

Using the Quadratic Formula, we can say that

x = ( -p ± √(p²-4(1)(q))) / 2(1)  with the 1 representing the coefficient of x². Simplifying, we get

x = ( -p ± √(p²-4q)) / 2

The roots of the function are therefore at

x = ( -p + √(p²-4q)) / 2 and x = ( -p - √(p²-4q)) / 2. The difference of the roots is thus

( -p + √(p²-4q)) / 2 - ( ( -p - √(p²-4q)) / 2)

= 0 + 2 √(p²-4q)/2

= √(p²-4q)

7 0
3 years ago
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