What is 6x + 9^3 factorsied

98 POINTS find the area of both the shaded regions

bonufazy [111]

Answer:

1. 40π/3

2. 18π

Step-by-step explanation:

For the first shaded region.

OA = OC

OD = OB

=> OA = 3+4 = 7 => R = 7

=> Circle area = π·7^2 = 49π

120/360 = 1/3 => The area of shaded region + mini region is (1/3)·49π = 49π/3

The area of white mini region with radius 3 is (1/3)·π·3^2 = 3π

=> The area of the shaded region is 49π/3 - 3π =

= 40π/3

For the second shaded region:

R = 9 cm.

Circle area = π·9^2 = 81π

80/360 = 2/9

=> The area of the shaded region is (2/9)×81π = 18π

7 0

3 years ago

Read 2 more answers

What is absolute value

jeka94

Absolute value is the distance between a point and 0. Absolute value is always positive. When you're writing numbers in absolute value, make sure you add:

| |

The absolute value of a negative number is also positive. For example:

| -7 | = 7 ⇒The absolute value of -7 is 7.

3 0

4 years ago

Please help me????22pts

worty [1.4K]

Answer:

$\mathrm{1 \dfrac{ 1 }{ 6 }\:cups}$

Step-by-step explanation:

Given from the graph:

There is $\frac{1}{2}$ cups of paint for one jar

There are 3 cups of paint for three jars

There is 1 $\frac{1}{2}$ cups of paint for one jar

There is 2 cups of paint for one jar

total amount of jars = 6

But since we need to find the amount of cups in each jar, we do:

$\dfrac{ 1 }{ 2 } +3+1 \dfrac{ 1 }{ 2 } +2$

Add $\frac{1}{2}$ and 1 $\frac{1}{2}$

$2+3+2$

Add 2 and 3

$5+2$

Add 5 and 2

$7$

total cups of paint = 7

Then we need to find how much paint could be splitted equally among the 6 jars, so we do the following:

total amount of jars = 6

total cups of paint = 7

We divide the total amount of jars by the total cups of paint

7 ÷ 6

Divide 7 by 6

$\dfrac{ 7 }{ 6 }$

$= 1 \dfrac{ 1 }{ 6 }$

$\mathrm{Answer: 1 \dfrac{ 1 }{ 6 }\:cups}$

7 0

3 years ago

If a door that is 36 inches in width opens to an angle of 140 , what is the length of the arc created by the door?

Fittoniya [83]

So hmm check the picture below

$\bf s=\cfrac{r\pi \theta}{180}\qquad 
\begin{cases}
s=\textit{length of the arc}\\
\theta=\textit{central angle in degrees}\\
r=radius\\
----------\\
r=36\\
\theta=140
\end{cases}\implies s=\cfrac{36\cdot \pi \cdot 140}{180}$

8 0

3 years ago

A study was conducted to determine whether an expectant mother’s cigarette smoking has any effect on the bone mineral content of

Helga [31]

Answer:

a) The samples are independent

b) $H_{0}$ : mu1=mu2*

$H_{a}$ : mu1≠mu2

c) There is no significant evidence that an expectant mother’s cigarette smoking has any effect on the bone mineral content of her otherwise healthy child

Step-by-step explanation:

Newborns whose mothers smoked during pregnancy and whose didn't smoke are two different populations. Therefore the samples are independent.

* Let mu1 be the mean bone mineral content of newborn babies whose mothers smoked during pregnancy

Let mu2 be the mean bone mineral content of newborn babies whose mothers didn't smoke during pregnancy

Null and alternative hypotheses are:

$H_{0}$ : mu1=mu2

$H_{a}$ : mu1≠mu2

Test statistic can be found using the equation:

$z=\frac{X-Y}{\sqrt{\frac{s(x)^2}{N(x)}+\frac{s(y)^2}{N(y)}}}$ where

X is the sample mean bone mineral content of newborn babies whose mothers smoked during pregnancy

Y is the sample mean bone mineral content of newborn babies whose mothers didn't smoke during pregnancy

s(x) is the sample standard deviation of bone mineral content of newborn babies whose mothers smoked during pregnancy

s(y) is the sample standard deviation of bone mineral content of newborn babies whose mothers didn't smoke during pregnancy

N(x) is the sample size for bone mineral content of newborn babies whose mothers smoked during pregnancy

N(y) is the sample size for bone mineral content of newborn babies whose mothers didn't smoke during pregnancy

$z=\frac{0.089-0.083}{\sqrt{\frac{0.022^2}{78}+\frac{0.023^2}{115}}}$ ≈1.825

two tailed p-value of test statistic is 0.068. Since 0.068>0.05, we fail to reject the null hypothesis. There is no significant evidence that an expectant mother’s cigarette smoking has any effect on the bone mineral content of her otherwise healthy child

7 0

3 years ago